What is the mass of helium atom whose atomic weight is 4.003 g/mol?
1 answer:
Answer:
Atoms He (Avogadro’s number) → Moles of He (molar mass of He) → Mass of He
• molar mass of He (from the periodic table) = 4.003 g/mol
• Avogadro’s Number: Avogadro’s number gives us the number of entities present in 1 mole: 6.022 × 1023 He atoms in 1 mole of He
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Answer:
<h3>The answer is 3.0 g/mL</h3>Explanation:
The density of a substance can be found by using the formula
From the question
mass = 15 g
volume = 5 mL
We have
We have the final answer as
<h3>3.0 g/mL</h3>Hope this helps you