The best and correct option is c
<h3><u>Answer;</u></h3>
2.4 atm
<h3><u>Explanation;</u></h3>
At constant temperature;
PV = constant
P1 = 1.2 atm
V1 = 0.25 L
P2 = ?
V2 = 0.125 L
But;
P1*V1 = P2*V2
Thus;
P2 = P1*V1/V2
= (1.2 atm)(0.25 L)/(0.125 L)
<u> = 2.4 atm</u>
No pressure
Ahhhhhh (filling character req)
Answer:
Cu2 + 2Mg-> 2Cu+ Mg2
Explanation:
Balance the equation and make sure both the reactant and the products are the same
Hope it will be helpful
Answer:
The substance that remained on the filter paper is Al(OH).
Explanation:
- Filter paper is the substance that is used in laboratory to separate the solid objects. It doesn't filter aqueous and gaseous products.
- So in our experiment the product formed is aluminum hydroxide Al(OH) and sodium chloride (NaCl).
- Between two products, sodium chloride is in aqueous form as indicated in the question. So it wont remain in the filter paper.
- Hence aluminum hydroxide being only solid product remains on the filter paper.
