When gasses are heated they emit only certain wavelengths of light (an emission line spectrum). Different gasses emit different wavelengths. A cool object (gas or solid) can absorb some of the light passing through it. The temperature of an object is a measure of how much energy its atoms have.
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Answer:
Reagent A = 
Reagent B= 
Intermediate C= δ-Valerolactone
Explanation:
In the reaction from the alkene to the alcohol, we can use the <u>alkene hydration</u> in which the hydronium ion is added to the double bond followed by the attack of water to produce the <u>alcohol</u>.
Then in the conversion from alcohol to ketone can be produced if an <u>oxidant reactive</u><u> </u>is used. In this case the <u>Jones reagent </u>(
).
The intermediate is a structure produced by a <u>peroxyacid</u>. This reaction would introduce an <u>ester group </u>in the cycle generating the δ-Valerolactone (Figure 1).
Answer:
a. At pH 9, the product, p-nitrophenol, will be ionized, the solution will appear yellow in color, and thus can be monitored at the wavelength of maximum absorption for the phenolate ion which is 400nm
Explanation:
In alkaline phosphatase assay, the hydrolysis of p nitrophenyl phosphate to p nitrophenol happens. When the ph is 9, the product which is p nitrophenol would undergo ionization. The solution is going to appear to be of yellow and it can be monitored at a wavelength for maximum absorption of phenolate ions at 400nm.
Option A is the answer to the question.
Explanation:
The answer is 0.5 moles of gold
Answer:
See explanation
Explanation:
Now we have, the graph attached.the stable disintegration product of C-14 is N-14.
Then;
Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;
N/No = (1/2)^t/t1/2
N = mass of C-14 at time t
No= mass C-14 originally present
t = time taken for N amount of C-14 to remain
No = mass of C-14 originally present
t1/2 = half life of C-14
N/64 = (1/2)^17,100/5730
N/64 = (1/2)^3
N/64 = 1/8
8N = 64
N = 8 g