The only bond that involves the complete transfer of electrons is ionic bonding.
A metal that does not have much care for its electrons, such as Sodium, Na, is willing to give up its electron more freely. And an atom that really cares about having electrons might be a gas such as chlorine, Cl. The Chlorine atom takes the electron from Sodium, and then the newly formed ions of Na+ and Cl- bond because they have equal and opposite charges and opposites attract. NaCl is formed.
Hydrogen bonds aren’t actually real bonds (I know, the name is deceptive)
Covalent bonds involve the sharing of electrons.
I’m pretty sure metallic bonds is a made-up term.
<span>You use the Henderson - Hasselbalch equation
pH = pKa + log ([salt]/[acid])
pKa = -log (8.2*10^-5) = 4.081
pH = 4.081 + (0.590/0.190)
pH = 4.081 + log 3.105
pH = 4.081 + 0.49206
pH = 4.573</span>
Answer:
the reaction will shift towards the “heat”—shifts to the left
Explanation:
To summarize:
o If temperature increases (adding heat), the reaction will shift away from the “heat” term and go in the
endothermic direction.
o If temperature decreases (removing heat), the reaction will shift towards the “heat” term and go in the
exothermic direction.
o NOTE: The endothermic direction is always away from the “heat” term and the exothermic direction is
towards the “heat” term.
Therefore the reaction will shift towards the “heat”—shifts to the left
Answer:
2.17 e -14
Explanation:
A strong acid like HCl ionize 100 % in water so [H3O+] = 0.46 M
[OH-] = Kw / [H3O+]
= 1.0 e -14 / 0.46
= 2.17 e -14
Answer:
A. Increasing the temperature will favor forward reaction and more CaCo3 formed.
B. More CaCo3 will be formed.
C. CaCo3 will decrease and more react ants formed.
D. Less CaCo3 will be formed.
E. Iridium is a catalyst so there is no effect
Explanation:
A. Temperature will increase because it's an endothermic reaction.
B. Adding Cao will favor forward reaction and more CaCo3 formed.
C. Removing methane, more react ants are formed and CaCo3 decreases.
D. Irridi is a catalyst so it has no effect on the CaCo3 but only speeds its rate of reaction.
