2 C8H18 + 25 O2 = 16 CO2 + 18 H2<span>O
Above is properly balanced but as you want 1 mole. divide everything by 2
</span>C8H18 + 12.5O2 = 8CO2 + 9H2<span>O</span>
This is an incomplete question, here is a complete question.
The reaction below has a Kp value of 3.3 × 10⁻⁵. What is the value of Kc for this reaction at 700 K?
Answer : The value of is,
Explanation :
The relation between and is:
where,
= equilibrium constant at constant pressure =
R = gas constant = 0.0821 L.atm/mol.K
T = temperature = 700 K
= change in number of gaseous moles = Product moles - Reactant moles = (2+1) - (2) = 3 - 1 = 1 mol
= equilibrium constant
Now put all the given values in the above expression, we get:
Therefore, the value of is,
Answer:
0.3139 nm
Explanation:
First of all, let's Calculate the average density of the Cr −Ta alloy;
Formula to get it is;
ρ_avg = 100/[(C_cr/ρ_cr) + (C_ta/ρ_ta)]
We are given;
C_cr = 26%
C_ta = 74%
ρ_cr = 7.13 g/cm³
ρ_ta = 16.6 g/cm³
Thus;
ρ_avg = 100/[(26/7.13) + (74/16.6)]
ρ_avg = 12.34 g/cm³
Similarly, let's Calculate the average atomic weight;
A_avg = 100/[(C_cr/A_cr) + (C_ta/A_ta)]
We are given;
A_cr = 52 g/mol
A_ta = 180.95 g/mol
Thus;
A_avg = 100/[(24/52) + (74/180.95)]
A_avg = 114.88 g/mol
Formula for the volume of the unit cell is;
V = n(A_avg)/(N_A × ρ_avg)
Where;
n is number of atoms in the cell which in this case = 2
N_A is avogadro's number = 6.022 × 10^(23)
Thus;
V = (2 × 114.88)/(6.022 × 10^(23) × 12.34)
V = 30.92 × 10^(-24) cm³
Length of the unit cell edge length is given by the formula;
a = ∛V
Thus;
a = ∛(30.92 × 10^(-24))
a = 0.00000003139 cm
Converting to metre, we have;
a = 0.3139 × 10^(-9) m = 0.3139 nm
Friction occurs when two surfaces come into contact. Excess friction hinders movement, and it wastes energy. Friction refers to a force that opposes motion. It is important because it is applied in almost all life processes.
Answer:
D
Explanation:
Photosphere is the layer where sunspots form.