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3 years ago

Human activities can have an impact on natural disasters.

2 answers:

6 0

I think you wanted to know whether the statement in question is true or false. Assuming this fact, i am answering the question and hope that it helps you. It is a true fact that human activities can have an impact on natural disasters. The increase in global temperature due to emission of greenhouse gases can cause the sea level to rise and create hurricanes.

alukav5142 [94]3 years ago

4 0

By definition, we have to:

The environmental impact are the consequences that some of the human activities produce on the environment.

The concept can be extended to the effects of a catastrophic natural phenomenon.

Human activities, such as fuel combustion and deforestation, have intensified the greenhouse effect, causing global warming.

It has been estimated that if emissions of greenhouse gases continue at the current rate, the temperature of the planet could exceed historical values in 2047, with harmful effects on ecosystems, biodiversity and endanger the livelihood of people on the planet.

Answer:

True.

Human activities can have an impact on natural disasters.

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A dancer moves around a path like the one

mash [69]

Given what we know, despite not having the figure attached to the question, we can still confirm that the magnitude for the acceleration of the dancer will be zero.

<h3>Why is the dancer's acceleration equal to zero?</h3>

This has to do with how the question clarifies the speed of the dancer. Though it does not give us an exact value, we are told that the speed is constant. This is an indicator that the acceleration is zero because with any other value for acceleration the speed <u>cannot remain</u> constant.

Therefore, given that any value for acceleration will increase or decrease the speed of the dancer, but we are told that the dancer's speed is constant throughout the trip, we can confirm that the magnitude for the acceleration of the dancer is zero.

To learn more about acceleration visit;

brainly.com/question/12134554?referrer=searchResults

7 0

2 years ago

Tina is driving her sports car down US1, traveling 27m/s. She sees her friend Rita up ahead, waiting to cross the street at the

mrs_skeptik [129]

Answer:

434 Hz

Explanation:

According to the Doppler effect, when a source of a wave is moving towards an observer at rest, then the observer will observe an apparent frequency which is higher than the original frequency of the source.

In this situation, Tina is driving towards Rita. Tina is the source of the sound wave (the horn), while RIta is the observer. Since the original frequency of the sound is 400 Hz, Rita will hear a sound with a frequency higher than this value.

The only choice which is higher than 400 Hz is 434 Hz, so this is the frequency that Rita will hear.

3 0

2 years ago

Wagon wheel. While working on your latest novel about settlers crossing the Great Plains in a wagon train, you get into an argum

OverLord2011 [107]

Answer:

I = 16.7kgm²

Explanation:

Since, Torque is given by,

\tau = F*r = I*\alpha

here, I = Moment of inertia = ??

\alpha = angular acceleration of wheel = a/r

F = tangential tension acting on the wheel = T

a = acceleration of bag of sand = 2.95 m/s^2

r = radius of wheel = d/2 = 120/2 = 60 cm = 0.60 m

from force balance on sand bag,

mg - T = m*a

T = m*(g-a)

m = mass of sand bag = 20 kg

So, I = T*r/\alpha = m*(g-a)*r/(a/r)

Using known values:

I = 20*(9.81 - 2.95)*0.60/(2.95/0.60) = 16.74

I = 16.7 kgm² = Moment of inertia of wheel experimentally

also, Moment of inertia of wheel theoretically(I') = M*r²

given, M = mass of wheel = 70 kg

I' = 70*0.60²= 25.2 kgm² = Moment of inertia of wheel theoretically

7 0

3 years ago

When was the Hubble telescope launched

SpyIntel [72]

Answer:

April 24, 1990 is the answer

5 0

3 years ago

Read 2 more answers

12. The diameter of a circle is 2.42m. Calculate its<br>area in proper significant figure

Sever21 [200]

Answer:

A = 4.6 [m²]

Explanation:

The area of a circle can be calculated by means of the following equation.

$A=\frac{\pi }{4} *D^{2}$

where:

A = area [m²]

D = diameter = 2.42 [m]

Now replacing:

$A=\frac{\pi }{4} *(2.42)^{2} \\A = 4.6 [m^{2} ]$

7 0

2 years ago