A galvanic cell is formed when two metals are immersed in solu- tions differing in concentration 1 when two different metals are immersed.
<h3>What is galvanic cell?</h3>
- The galvanic cell utilizes the ability to split the flow of electrons in the process of oxidization and reduction, compelling a half-reaction and connecting each with a wire so that a way can be formed for the flow of electrons via such wire.
- A galvanic cell is an electrochemical cell that transforms the chemical energy of a spontaneous redox response into electrical energy. It has an electrical possibility equal to 1.1 V. In galvanic cells, oxidation occurs at the anode and it is a negative plate. Lessening occurs at the cathode and it is a positive plate.
- A galvanic cell is an electrochemical cell that converts the free liveliness of a chemical method into electrical energy. A photogalvanic cell generates species photochemically which react resulting in an electrical current via an external circuit.
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Speed and direction are the two scientific componets that make up velocity.
The period T of a pendulum is given by:
where L is the length of the pendulum while
is the gravitational acceleration.
In the pendulum of the problem, one complete vibration takes exactly 0.200 s, this means its period is
. Using this data, we can solve the previous formula to find L:
The mass of a planet determines the acceleration due to gravity on it. This is according to Newton's Law of Gravitation, which basically states that the more mass a body has, the greater the force of attraction it exerts on other bodies with mass near it.
The gravitational force is:
F = GMm/r², where G is a constant, r is the distance between large mass M and small mass m.
Considering the fact that acceleration is force per unit mass, if we divide gravitational force by the small mass (to get force per unit mass), we see the dependence mathematically:
a = GM/r²
Answer:
(A) Distance will be equal to 1.75 km
(B) Displacement will be equal to 1.114 km
Explanation:
We have given circumference of the circular track = 3.5 km
Circumference is given by 
r = 0.557 km
(a) It is given that car travels from southernmost point to the northernmost point.
For this car have to travel the distance equal to semi perimeter of the circular track
So distance will be equal to 
(b) If car go along the diameter of the circular track then it will also go from southernmost point to the northernmost point. and it will be equal to diameter of the track
So displacement will be equal to d = 2×0.557 = 1.114 m
