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jeyben [28]
3 years ago
12

Agreen wire that channels electrons away from a power surge is also called a.

Physics
1 answer:
Katen [24]3 years ago
5 0
Should be B I took the same
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What is the intensity of 60dB sound?​
polet [3.4K]

Answer:

The intensity of the sound in W/m² is 1 x 10⁻⁶ W/m².

Explanation:

Given;

intensity of the sound level, dB = 60 dB

The intensity of the sound in W/m² is calculated as;

dB = 10 Log[\frac{I}{I_o} ]\\\\

where;

I₀ is threshold of hearing = 1 x 10⁻¹² W/m²

I is intensity of the sound in W/m²

Substitute the given values and for I;

dB = 10 Log[\frac{I}{I_o} ]\\\\60 = 10 Log[\frac{I}{I_o} ]\\\\6 =  Log[\frac{I}{I_o} ]\\\\10^6 = \frac{I}{I_o} \\\\I = 10^6 \ \times \ I_o\\\\I = 10^6 \ \times \ 1^{-12} \ W/m^2 \\\\I = 1\ \times \ 10^{-6} \ W/m^2

Therefore, the intensity of the sound in W/m² is 1 x 10⁻⁶ W/m².

5 0
3 years ago
Write an equation that expresses the first law of thermodynamics in terms of heat and work.
OleMash [197]

Answer:

Heat Input = Work Output       (at 100% efficiency)

ΔQ = ΔW

(you cannot get something for nothing)

3 0
1 year ago
Can someone help me with this science question
Anettt [7]
Mechanical layers of the earth:

-Lithosphere
-Asthenosphere
-Mesosphere
-Outer Core
-Inner Core


Chemical layers of the earth:

-Crust
-Mantle
-Core



Hope this helps

Have a great weekend! :)
6 0
3 years ago
Read 2 more answers
The knob of a door always has a larger radius than the shaft so that the distance over which the force is applied _______ in ord
4vir4ik [10]
Is greater
Reduce......................
4 0
3 years ago
Read 2 more answers
A certain substance has a heat of vaporization of 37.51 kJ / mol. At what Kelvin temperature will the vapor pressure be 3.50 tim
stellarik [79]

Answer:

T2=336K

Explanation:

Clausius-Clapeyron equation is used to determine the vapour pressure at different temperatures:

where:

In(P2/P1) = ΔvapH/R(1/T1 - 1/T2)

p1 and p2 are the vapour pressures at temperatures 

T1 and T2

ΔvapH = the enthalpy  of vaporization of the liquid

R = the Universal Gas Constant

p1=p1, T1=307K

p2=3.50p1; T2=?

ΔvapH=37.51kJ/mol=37510J/mol

R=8.314J.K^-1moL^-1

In(3.50P1/P1)= (37510J/mol)/(8.314J.K^-1)*(1/307 - 1/T2)

P1 and P1 cancelled out:

In(3.50)=4511.667(T2 - 307/307T2)

1.253=14.696(T2 - 307/T2)

1.253=(14.696T2) - (14.696*307)/T2

1.253T2=14.696T2 - 4511.672

Therefore,

4511.672=14.696T2 - 1.253T2

4511.672=13.443T2

So therefore, T2=4511.672/13.443=335.61

Approximately, T2=336K

6 0
3 years ago
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