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Ilya [14]
2 years ago
5

Which two options are examples of waves reflecting?

Physics
2 answers:
Murljashka [212]2 years ago
7 0

Answer:

D

Explanation:

Your image in a mirror

Zinaida [17]2 years ago
3 0
I think the answer is b
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Describe the orbital diagram of an atom with 16 electrons
Korvikt [17]

Answer:

The orbital diagram represents the filling of electrons in the sub levels of an orbit. The filling of the orbitals in sub- levels follow some basic rules and principles.

The orbital diagram of an orbit containing 16 electrons will be as follows:

    1s²2s²2p⁶3s²3p⁴

  • The maximum number of electrons in each sublevel of the orbitals are:
  •                  2 electrons for s-sublevel with one orbital
  •                  6 electrons for p-sublevel with three orbital
  •                  10 electrons for d-sublevel with five orbital
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5 0
3 years ago
Convert the following measurements. Only type numbers and decimals into the answer boxes:
ivolga24 [154]

Answer:

2m 4m2Explanation:rteji3ujnrej

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3 years ago
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Two lab carts are pushed together with a spring mechanism compressed between them. Upon release, the 5.0 kg cart repels one way
JulijaS [17]

Answer:

V = -0.3 m/sec.

Explanation:

5.0 x 0.12 + 2.0 x v = 0. Which means that V = -0.3 m/sec.

The -ve sign shows it moves in the opposite direction.

8 0
3 years ago
Physics Question: Determine the work that is being done by tension in pulling the box 193.0 cm along the table. Also determine t
lozanna [386]

1) The work done by tension is 12.0 J

2) The final speed of the box is 1.57 m/s

Explanation:

The work done by a force on an object is given by:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and of the displacement

For the box in this problem, we have:

F = 6.2 N is the force applied (the tension in the string)

d = 193.0 cm = 1.93 m is the displacement

\theta=0 assuming that the string is horizontal

Substituting, we find the work done by the tension:

W=(6.2)(1.93)(cos 0)=12.0 J

2)

In order to determine the final speed of the box, we need to determine its acceleration first.

Beside the tension, acting forward, the other force acting horizontally on the box is the force of friction, whose magnitude is

F_f = \mu mg

where

\mu=0.16 is the coefficient of friction

m = 2.8 kg is the mass of the box

g=9.8 m/s^2 is the acceleration of gravity

Substituting,

F_f = (0.16)(2.8)(9.8)=4.4 N

Therefore, the net force on the box is

F=6.2  N - 4.4 N = 1.8 N

And the acceleration can be found by using Newton's second law:

F=ma

where

F = 1.8 N is the net force

m = 2.8 kg is the mass of the box

a is the acceleration

Solving for a,

a=\frac{F}{m}=\frac{1.8}{2.8}=0.64 m/s^2

Now we can finally find the final speed using the suvat equation:

v^2-u^2=2as

where

v is the final speed

u = 0 is the initial speed

a=0.64 m/s^2 is the acceleration

s = 1.93 m is the displacement

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(0.64)(1.93)}=1.57 m/s

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
3 years ago
What instrument did navigators use to calculate the positions of the sun and the stars?
Taya2010 [7]
Navigators used astrolabes to calculate positions of the sun and stars.
8 0
3 years ago
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