Answer:
25.12
Step-by-step explanation:
brainliest please
The product of the sum of two perfect cubes:
a³ + b³ = (a + b)(a² - ab + b²)
The product of the difference of two perfect cubes:
a³ - b³ = (a - b)(a² + ab + b²)
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Remember to follow FOIL:
(b^2 + 8)(b^2 - 8)
(b^2)(b^2) = b^4
(b^2)(-8) = -8b^2
(8)(b^2) = 8b^2
(8)(-8) = -64
b^4 - 8b^2 + 8b^2 - 64
Combine like terms:
b^4 (-8b^2 + 8b^2) - 64
b^4 - 64
b^4 - 64 is your answer
hope this helps
Given:
x and y are both differentiable functions of t.


To find:
The value of
.
Solution:
We have,
...(i)
At x=-1,




Divide both sides by 3.

Taking cube root on both sides.

So, y=2 at x=-1.
Differentiate (i) with respect to t.

Putting x=-1, y=2 and
, we get



Divide both sides by -8.


Therefore, the value of
is 36.
Answer:
84
Step-by-step explanation:
Answer:
Step-by-step explanation: