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3 years ago

Round 69581.491337 to the nearest thousand.

Mathematics

1 answer:

jolli1 [7]3 years ago

3 0

Answer: So rounding 69581.491337 to the nearest thousand is

70000

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Adrian

Goshia [24]

Answer:

Hence, both Marlon and Adrian both have the same at bats percentage.

Step-by-step explanation:

Marlon's at bats :

Number of at bats = 15

Hits = 6

Hit percentage = 6/15 * 100% = 40%

Adrian :

Number of at bats = 10

Hits = 4

Hit percentage = 4/10 * 100% = 40%

Hence, both Marlon and Adrian both have the same at bats percentage.

5 0

3 years ago

Identify the initial amount a and the growth factor b in the exponential function a(x) =680•4.3^

Anna35 [415]

f(x) = 680 ( 4 )³
a b

8 0

3 years ago

Radium-228 has a half-life of 5.75 years. What is the decay rate for radium-228?

artcher [175]

Decay rate for Radium-228 is 0.01205

Step-by-step explanation:

The half life of radium-228 is 5.75 years. We need to find the decay rate for radium.

The formula used is:

$ln\frac{N_o}{N_t}=-\lambda t$

Where N₀ = amount of radioactive particles at time = 0

N_t = amount of radioactive particles are time (t)

λ = rate of decay constant

t = time

We are given half life so, $\frac{N_o}{N_t}$ =0.5

t= 5.75 years

We need to find λ

Putting values in formula and solving:

$ln\frac{N_o}{N_t}=-\lambda t$

$ln(0.5)=-\lambda *5.75\\-\lambda=\frac{ln(0.5)}{5.75}\\-\lambda=\frac{-0.69}{5.75}\\-\lambda=-0.1205\\\lambda=0.1205$

So, Decay rate for Radium-228 is 0.01205.

Keywords: Decay Rate

Learn more about Decay Rate at:

#learnwithBrainly

3 0

4 years ago

A 200 kg sailboat experiences an unbalanced force of 895 N pushing it forward, what is the sailboat's acceleration?

tankabanditka [31]

Answer:

4.5m/s^2

Step-by-step explanation:

Given data

Mass= 200kg

Force= 895N

Required

the acceleration a

We know that

F=ma

a= F/m

substitute

a= 895/200

a= 4.5 m/s^2

Hence the accelaration is 4.5m/s^2

4 0

3 years ago

HELPPP!

Anika [276]

Answer:

c. x ≈ 1.71, y ≈ 6.29, z ≈ 60.71

Step-by-step explanation:

You are at a bit of a disadvantage with this problem, because both the hint and the answer choices are incorrect.

The matrix equation is ...

$AX=B\\\\\left[\begin{array}{ccc}-1&1&0\\4&3&0\\1&-7&1\end{array}\right]\left[\begin{array}{c}x&y&z\end{array}\right]=\left[\begin{array}{c}8&12&15\end{array}\right]$

Contrary to what the hint is telling you, the multiplication by the inverse must be on the left:

$A^{-1}AX=A^{-1}B\\\\X=A^{-1}B$

Using appropriate tools to compute the inverse, this becomes ...

$\left[\begin{array}{c}x&y&z\end{array}\right]=\dfrac{1}{7}\left[\begin{array}{ccc}-3&1&0\\4&1&0\\31&6&7\end{array}\right]\left[\begin{array}{c}8&12&15\end{array}\right]\\\\\left[\begin{array}{c}x&y&z\end{array}\right]=\dfrac{1}{7}\left[\begin{array}{c}-12&44&425\end{array}\right]\approx\left[\begin{array}{c}-1.714&6.286&60.714\end{array}\right]$

The closest match is choice C.

6 0

4 years ago