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Anestetic [448]
3 years ago
7

A gardener is planting two types of trees:Type A is three feet tall and grows at a rate of 15 inches per year.Type B is four fee

t tall and grows ata rate of 10 inches per year.Algebraically determine exactly many years it will take for these trees to be the same heighthow

Mathematics
1 answer:
Sliva [168]3 years ago
7 0
First, construct two equations.
Then, equal the two equations to each other like this -

x will be the years.

Type A. Type B

3x + 15 = 4x + 10
- 15. - 15

3x = 4x - 5
-4x. -4x

-x = -5
-x/-1 = -5/-1
x = 5

Check:

3(5) + 15 = 4(5) + 10
15 + 15 = 20 + 10
30 = 30

Therefore, the trees will be the same height in 5 years.
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Answer:

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Answer and Step-by-step explanation:

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kobusy [5.1K]
Okay, I think I understand this. Our first step is to solve how long the string is after he used some of it to tie the package. I have a feeling we have to subtract 7/8 - 1/5. Find a least common multiple (in this case, it's 40) and our new fractions are 35/40 and 8/45. Subtract:

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I don't think this can be simplified down any further as they do not have any common factors. So with that in mind, let's divide 27/40 with 5/1 (5/1 is basically 5 wholes but in fraction version)

When dividing fractions, you want to use the KCF technique (my old math teacher taught me this). Keep the first fraction the same (in this case, 27/40), change the sign from multiplication to division, and flip 5/1 to get it's reciprocal, 1/5. The equation will look like this:

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If this is wrong, please let me know, but this is what I got out of this question. I hope this helped you :)
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