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Debora [2.8K]
2 years ago
9

In which way are the cathode rays deflected in the x-plates of the Cathode Ray Oscilloscope​

Physics
2 answers:
DerKrebs [107]2 years ago
5 0

Answer:

vertically

Explanation:

  • Cathode ray Oscilloscope or Cathode ray discharge tube is made of glass is taken with two electrodes.
  • It was used by JJ Thompson to discover electrons
  • The experiment is popularily called cathode ray discharge tube experiment
MrRissso [65]2 years ago
4 0

Answer:

The cathode ray is deflected vertically to the fluorescent screen

Explanation:

.

You might be interested in
The property that describes how radily a substance combines chemically with other substances is _____________
goldfiish [28.3K]

This is reactivity. It describes how easily one substance reacts with another

4 0
3 years ago
An air bubble has a volume of 1.70 cm³ when it is released by a submarine 115 m below the surface of a lake. What is the volume
Natalija [7]

Answer:

V = 20.67 cm³

Explanation:

In this case, let's apply the Boyle's law which is:

P1V1 = P2V2

Where P1 and V1 would be condition in the water, and P2 and V2 would be the condition at the surface.

By logic, at the surface, pressure should be equals to 1 atm or 1.01x10^5 N/m²

We know the volume of the bubble at first which is 1.70 cm³ and we need to calculate V2. We know how much is P2, but we don't know the value of P1, which is the pressure of the bubble below the sea; this can be calculated using Pascal's principle which is the following expression:

P1 = Po + dgh

Where:

Po: innitial pressure, which we can assume is 1 atm

d = density of the substance, in this case, water (1000 kg/m³)

g = gravity (9.8 m/s²)

h = distance of the bubble from the surface (115 m)

Now replacing this data in the boyle's law we have the following:

P1V1 = P2V2

V2 = P1V1/P2

V2 = (Po + dgh) * V1 / P2

Replacing the data we have:

V2 = (1.01x10^5 + 1000*9.8*115) * 1.7 / 1.01x10^5

V2 = 2,087,600 / 1.01x10^5

V2 = 20.67 cm³

5 0
3 years ago
URGENT!!!!!!!<br><br> PLEASE HELP WITH THIS PHYSICS PROBLEM
Levart [38]

Explanation:

Let

x_1 = distance traveled while accelerating

x_2 = distance traveled while decelerating

The distance traveled while accelerating is given by

x_1 = v_0t + \frac{1}{2}at^2 = \frac{1}{2}at^2

\:\:\:\:\:= \frac{1}{2}(2.5\:\text{m/s}^2)(30\:\text{s})^2

\:\:\:\:\:= 1125\:\text{m}

We need the velocity of the rocket after 30 seconds and we can calculate it as follows:

v = at = (2.5\:\text{m/s}^2)(30\:\text{s}) = 75\:\text{m/s}

This will be the initial velocity when start calculating for the distance it traveled while decelerating.

v^2 = v_0^2 + 2ax_2

0 = (75\:\text{m/s})^2 + 2(-0.65\:\text{m/s}^2)x_2

Solving for x_2, we get

x_2 = \dfrac{(75\:\text{m/s})^2}{2(0.65\:\text{m/s}^2)}

\:\:\:\:\:= 4327\:\text{m}

Therefore, the total distance x is

x = x_1 + x_2 = 1125\:\text{m} + 4327\:\text{m}

\:\:\:\:= 5452\:\text{m}

3 0
3 years ago
The atmospheric pressure at the surface of titan is.
Harrizon [31]

Answer:

about 1.5 bars

Titan's atmosphere is similar to Earth's both in the predominance of nitrogen gas and in surface pressure, which is about 1.5 bars, or 50 percent higher than sea-level pressure on Earth.

Explanation:

8 0
1 year ago
If a car has a velocity of 40 km/h west and then comes to a stop in 5 s, what is its acceleration in m/s2?
Leno4ka [110]

acceleration = change in velocity /change in time

convert 40km to meter then divide it with 5

6 0
2 years ago
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