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trapecia [35]
3 years ago
6

1+-w2+9w and I need help cuz I’m on 76 and I’m sooo close help

Mathematics
1 answer:
Gnesinka [82]3 years ago
4 0

\huge \boxed{\mathfrak{Question} \downarrow}

  • Simplify :- 1 + - w² + 9w.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\large \sf1 + - w ^ { 2 } + 9 w

Quadratic polynomial can be factored using the transformation \sf \: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where \sf x_{1} and x_{2} are the solutions of the quadratic equation \sf \: ax^{2}+bx+c=0.

\large \sf-w^{2}+9w+1=0

All equations of the form \sf\:ax^{2}+bx+c=0 can be solved using the quadratic formula: \sf\frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

\large \sf \: w=\frac{-9±\sqrt{9^{2}-4\left(-1\right)}}{2\left(-1\right)}  \\

Square 9.

\large \sf \: w=\frac{-9±\sqrt{81-4\left(-1\right)}}{2\left(-1\right)}  \\

Multiply -4 times -1.

\large \sf \: w=\frac{-9±\sqrt{81+4}}{2\left(-1\right)}  \\

Add 81 to 4.

\large \sf \: w=\frac{-9±\sqrt{85}}{2\left(-1\right)}  \\

Multiply 2 times -1.

\large \sf \: w=\frac{-9±\sqrt{85}}{-2}  \\

Now solve the equation \sf\:w=\frac{-9±\sqrt{85}}{-2} when ± is plus. Add -9 to \sf\sqrt{85}.

\large \sf \: w=\frac{\sqrt{85}-9}{-2}  \\

Divide -9+ \sf\sqrt{85} by -2.

\large \boxed{ \sf \: w=\frac{9-\sqrt{85}}{2}} \\

Now solve the equation \sf\:w=\frac{-9±\sqrt{85}}{-2} when ± is minus. Subtract \sf\sqrt{85} from -9.

\large \sf \: w=\frac{-\sqrt{85}-9}{-2}  \\

Divide \sf-9-\sqrt{85} by -2.

\large \boxed{ \sf \: w=\frac{\sqrt{85}+9}{2}}  \\

Factor the original expression using \sf\:ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \sf\frac{9-\sqrt{85}}{2}for \sf\:x_{1} and \sf\frac{9+\sqrt{85}}{2} for \sf\:x_{2}.

\large \boxed{ \boxed {\mathfrak{-w^{2}+9w+1=-\left(w-\frac{9-\sqrt{85}}{2}\right)\left(w-\frac{\sqrt{85}+9}{2}\right) }}}

<h3>NOTE :-</h3>

Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

\large \sf \: 1 + -  w {}^{2}  + 9w \\  =\large  \boxed{\bf \: 1 -  {w}^{2}   + 9w}

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)

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Write two ratios equivalent to 24 : 9.
notsponge [240]

Answer:

8:3

16:6

Step-by-step explanation:

First, let's check if 9 and 24 have any common factor. If they do have any common ones, we must find the GCF (greatest common factor).

Factors of 9: 1, 3, 9

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

The common factors both of the numbers share and 1 and 3. To find the GCF, simply compare one of the factors to the other.

1 < 3

Now that we know the GCF, we can divide the two numbers in the ratio 24 : 9 by it (3).

24:9

24/3:9/3

<u>8:3</u>

Now that our ratio is simplified, it's going to be much easier to find more ratios that are equivalent. <u>8:3</u> is already one equivalent ratio, but if we multiply each number in the ratio by any other number, we can get a new equivalent ratio. Let's multiply each number in the ratio by 2:

<u>8:3</u>

8 ⋅ 2:3 ⋅ 2

<u>16:6</u>

<u></u>

So, another equivalent ratio to 24:9 (and <u>8:3</u>) is <u>16:6</u>.

3 0
3 years ago
What decimal is equivalent to negative 3/8
Fittoniya [83]

Answer:

-6/16

Step-by-step explanation:

<u>Step 1:  Find equivalent to -3/8</u>

(-3*2) / (8*2)

<em>-6/16</em>

Answer:  -6/16

7 0
3 years ago
Read 2 more answers
If the trapezoid on the grid below is translated by using the rule (x,y)-&gt; (x-4,y-3) what will be the coordinates of B’?
vesna_86 [32]

Answer:

B'(3, 5)

Step-by-step explanation:

Rule for the translation of a point (x, y) by 'h' units left and 'k' units upwards,

(x, y) → (x - h, y + k)

If h = 4 and k = 3,

(x, y)\rightarrow(x-4,y+3)

Following this rule coordinates of the image point of B will be,

B(7, 2) → B'(7 - 4, 2 + 3)

           → B'(3, 5)

Therefore, coordinates of the image point B' will be,

B'(3, 5)

6 0
3 years ago
If (-2,4) are the coordinates of a point on the line whose equation is y=Mx+1 , what is the slope of the line?
horrorfan [7]

Slope of the line is -3/2

Step-by-step explanation:

  • Step 1: Given that (-2, 4) is a point on the line y = mx + 1, find slope m.

Since the point is on the line, the coordinates will satisfy the equation.

⇒ 4 = m × -2 + 1

⇒ 4 = -2m + 1

⇒ 3 = -2m

∴ m = -3/2

5 0
3 years ago
PLEASE HELP IMMEDIATELY!!!
kkurt [141]

Answer:

x = -33

Step-by-step explanation:

2/3(x+6)=-18

Multiply each side by 3/2

3/2*2/3(x+6)=-18*3/2

x+6 = -27

Subtract 6 from each side

x+6-6 = -27-6

x = -33

7 0
3 years ago
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