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mario62 [17]
3 years ago
11

Which of the following mixture types canNOT be filtered to remove solutes?

Chemistry
1 answer:
iVinArrow [24]3 years ago
3 0
1. A) Colloids only

2. C) M<span>olecules of the dispersion medium colliding with dispered phase particles 

Hope this helps!</span>
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The solubility of potassium sulfate in water is 16 grams per 100
kicyunya [14]

The answer is 25 grams for this question

7 0
2 years ago
Which of the following could be the subsh
andreev551 [17]

Answer:

2s^2 2p^2

Explanation:

Group 4A contains a total of 4 electrons for each atom in their valence shell. Filling the orbital diagram, let's say, for carbon, notice that when we start with period 2, we have two elements in the s-block, that is, lithium and beryllium. They correspond to the two s electrons that belong to the valence shell of carbon.

Moving on, we have boron and carbon, the remaining 2 electrons. Now, starting with boron, we're in the p-block.

That said, looking at the second period, the electron configuration for the valence shell of a group 4A element would be:

2s^2 2p^2

6 0
3 years ago
You have a red ballooe that has a volume of 20 liters, a pressure of 1.5 atmospheres and a temperature of 28 C. What is the volu
ki77a [65]

Explanation:

The given data is as follows.

 P_{1} = 1.5 atm,     V_{1} = 20 L,  T_{1} = (28 + 273) K = 301 K

   P_{2} = 5 atm,     V_{2} = ?,  T_{2} = (50 + 273) K = 323 K

Formula to calculate the volume will be as follows.

         \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}

Putting the given values into the above formula as follows.

        \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}  

        \frac{1.5 atm \times 20 L}{301 K} = \frac{5 atm \times V_{2}}{323 K}  

                 V_{2} = 0.64 L

Thus, we can conclude that the change in volume of the balloon will be 0.64 L.

6 0
3 years ago
What type of large molecule is responsible for repair and growth of cells?
Oliga [24]

Answer:

The answer is a. proteins

7 0
3 years ago
Read 2 more answers
Draw the Lewis structure for methane (CH4) and ethane (C2H6) in the box below. Then predict which would have the higher boiling
Alinara [238K]

Answer:

Ethane would have a higher boiling point.

Explanation:

In this case, for the lewis structures, we have to keep in mind that all atoms must have <u>8 electrons</u> (except hydrogen). Additionally, each carbon would have <u>4 valence electrons</u>, with this in mind, for methane we have to put the hydrogens around the carbon, and with this structure, we will have 8 electrons for the carbon. In ethane, we will have a bond between the carbons, therefore we have to put three hydrogens around each carbon to obtain 8 electrons for each carbon.

Now, the main difference between methane and ethane is an <u>additional carbon</u>. In ethane, we have an additional carbon, therefore due to this additional carbon, we will have <u>more area of interaction</u> for ethane. If we have more area of interaction we have to give <u>more energy</u> to the molecule to convert from liquid to gas, so, the ethane will have a higher boiling point.

I hope it helps!

7 0
3 years ago
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