What is 0.999 repeating decimal as a fraction

it is known that a certain lacrosse goalie will successfully make a save 85.11 % of the time. Suppose that the lacrosse goalie a

Lostsunrise [7]

$P(X\geq10)=P(X=10)+P(X=11)+P(X=12)=\binom{12}{10}p^{10}(1-p)^2+\cdots=73.95\%$

4 0

3 years ago

Read 2 more answers

Please help me with geometry

spayn [35]

For each sub-problem shown below, I'm using the distance formula to compute the distance between the two points

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For the points (-10,2) and (-2,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-10))^2+(2-2)^2)

d = sqrt((-2+10)^2+(2-2)^2)

d = sqrt((8)^2+(0)^2)

d = sqrt(64+0)

d = sqrt(64)

d = 8

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For the points (-3,-1) and (5,1), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-(-3))^2+(1-(-1))^2)

d = sqrt((5+3)^2+(1+1)^2)

d = sqrt((8)^2+(2)^2)

d = sqrt(64+4)

d = sqrt(68)

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For the points (-3,-2) and (1,3), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-(-3))^2+(3-(-2))^2)

d = sqrt((1+3)^2+(3+2)^2)

d = sqrt((4)^2+(5)^2)

d = sqrt(16+25)

d = sqrt(41)

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For the points (-3,-5) and (-2,-4), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-3))^2+(-4-(-5))^2)

d = sqrt((-2+3)^2+(-4+5)^2)

d = sqrt((1)^2+(1)^2)

d = sqrt(1+1)

d = sqrt(2)

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For the points (0,0) and (5,5), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-0)^2+(5-0)^2)

d = sqrt((5)^2+(5)^2)

d = sqrt(25+25)

d = sqrt(50)

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For the points (1,2) and (1,-10), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-1)^2+(-10-2)^2)

d = sqrt((0)^2+(-12)^2)

d = sqrt(0+144)

d = sqrt(144)

d = 12

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For the points (1,2) and (5,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-1)^2+(2-2)^2)

d = sqrt((4)^2+(0)^2)

d = sqrt(16+0)

d = sqrt(16)

d = 4

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For the points (2,3) and (10,9), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((10-2)^2+(9-3)^2)

d = sqrt((8)^2+(6)^2)

d = sqrt(64+36)

d = sqrt(100)

d = 10

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See the attached image for how the answers match up (take note of the letter labels)

3 0

4 years ago

find the smaller of 2 consecutive integers, x, if the sum of the smaller is 3 times the larger is -5. Write an equation and solv

Leno4ka [110]

You have defined x to be the smaller of two consecutive integers. Then the larger will be (x+1). The given relation is

... (x) + 3(x+1) = -5 . . . . the smaller plus 3 times the larger is -5

... 4x + 3 = -5 . . . . . . . .simplify

... 4x = -8 . . . . . . . . . . subtract 3

... x = -2 . . . . . . . . . . . divide by the coefficient of x

The smaller of the two integers is -2.

5 0

3 years ago

Add (3x + 9 / 2x + 6) + (8x + 12 / x^2 + 6x + 9)

jenyasd209 [6]

Answer:

$\dfrac{3x^2+34x+51}{2x^2+12x+18}$

Step-by-step explanation:

$\dfrac{3x+9}{2x+6}+\dfrac{8x+12}{x^2+6x+9}= \\\\\\\dfrac{3(x+3)}{2(x+3)}+\dfrac{8x+12}{(x+3)(x+3)}$

To add these two fractions, you need to make the denominators equal:

$\dfrac{3(x+3)(x+3)}{2(x+3)(x+3)}+\dfrac{16x+24}{2(x+3)(x+3)}= \\\\\\\dfrac{(3x^2+18x+27)+(16x+24)}{2(x+3)(x+3)}= \\\\\\\dfrac{3x^2+34x+51}{2(x+3)(x+3)}= \\\\\\\dfrac{3x^2+34x+51}{2x^2+12x+18}$

Hope this helps!

4 0

4 years ago

Please help<br> Solve for x.

Olegator [25]

Sum of interior angles = (n-2) × 180<span> = (5-2) x 180 = 3 x 180 = 540

so
x + 90 + 107 + 144 + 138 = 540
x + 479 = 540
x = 540 - 479
x = 61</span>

5 0

4 years ago