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3 years ago

An object starts at 4m/s and accelerates to 6m/s in 10 seconds. Find its displacement.

Physics

1 answer:

Natalka [10]3 years ago

6 0

Answer:

Explanation:

The 2 equations we need here are, first:

$a=\frac{v_f-v_0}{t}$ and then once we solve for the acceleration here:

$v^2=v_0^2+2a$ Δx

Solving for acceleration:

$a=\frac{6-4}{10}=\frac{1}{5}\frac{m}{s^2}$ and now we will use that in the other equation:

$6^2=4^2+2(\frac{1}{5})$ Δx and

36 = 16 + $\frac{2}{5}$ Δx and

20 = $\frac{2}{5}$ Δx and

$\frac{5}{2}(20)=$ Δx so

Δx = 50 m

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Consider three drinking glasses. All three have thesame area base, and all three are filled to the same depth withwater. Glass A

Sergio [31]

Answer:

The correct answer is C. All three have equal non-zero pressure

Explanation:

Pressure is the relationship between the force and the area of a body, when the bodies are liquid the formula that

P = rho g h

Where rho is the density and h the height of the liquid

We see that for this expression the pressure does not depend on the shape of the container, but on its height, as the three vessels have the same height, the pressure at the bottom is the same.

The correct answer is C All three have equal non-zero pressure

8 0

3 years ago

Can anyone help me with these questions? TIA!<br> (Don’t actually answer please! :) )

nataly862011 [7]

<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Question 7: </h2>

$\huge\text{Graphs:}$

The graph of

• The I-V for Ohmic Metal wire conductor at constant temperature always shows a straight line between the Current(I) plotted at Y axis and Voltage(V) plotted at X axis. Picture 1

• The I-V graph for Diode shows that first the current is zero but as we increase the potential difference(voltage), it results in the increase in the current. Picture 2

<h2>_____________________________________ </h2><h2>Question 8: </h2>

$\Large\textbf{Diode:}$

A diode is a device that allows current to flow in only one direction.

$\Large\textbf{Forward and Reverse Biasing:}$

Forward Bias, When a diode is forward bias (a voltage in the "forward" direction) then the P-side of the diode is attached to the positive terminal and N-side is fixed to the negative side of the battery which is connected, current flows freely through the device. The forward bias decreases the thickness of potential barrier(The potential barrier barrier in which the charge requires additional force for crossing the region)

Reverse Bias, When a diode is Reverse bias(a voltage in the "backward direction) then the P-side of the diode is connected to the negative terminal and N-side is connected to the positive terminal of the battery which is connected. The reverse bias increases the thickness of the potential barrier resulting in the flow of no current.

$\Large\textbf{Answer to the Question "Resistance"}$

The Forward bias decreases the resistance of the diode whereas the reversed bias increases the resistance of the diode. As in forward biasing the current is easily flowing through the circuit whereas reverse bias does not allow the current to flow through it.

<h2>_____________________________________ </h2><h2>Best Regards, </h2><h2>'Borz' </h2>