Complete Question
An isolated charged soap bubble of radius R0 = 7.45 cm is at a potential of V0=307.0 volts. V0=307.0 volts. If the bubble shrinks to a radius that is 19.0%19.0% of the initial radius, by how much does its electrostatic potential energy ????U change? Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble r
Answer:
The difference is 
Explanation:
From the question we are told that
The radius of the soap bubble is 
The potential of the soap bubble is 
The new radius of the soap bubble is 
The initial electric potential is mathematically represented as
The final electric potential is mathematically represented as
The initial potential is mathematically represented as
The final potential is mathematically represented as
Now
substituting values
=> 
So
Therefore
![U_f -U_i = \frac{V_1^2}{2k} [\frac{ R_1 }{ * 0.19^2} - R_o]](https://tex.z-dn.net/?f=U_f%20-U_i%20%3D%20%20%20%20%20%5Cfrac%7BV_1%5E2%7D%7B2k%7D%20%5B%5Cfrac%7B%20R_1%20%7D%7B%20%2A%200.19%5E2%7D%20-%20R_o%5D)
where k is the coulomb's constant with value 
substituting values
![U_f -U_i = \frac{307^2}{9 * 10^{9}} [\frac{ 0.014155 }{ 0.19^2} - 0.0745]](https://tex.z-dn.net/?f=U_f%20-U_i%20%3D%20%20%20%20%20%5Cfrac%7B307%5E2%7D%7B9%20%2A%2010%5E%7B9%7D%7D%20%5B%5Cfrac%7B%200.014155%20%7D%7B%200.19%5E2%7D%20-%200.0745%5D)
Answer:
the time at which it passes through the equilibrum position is:
t = 0.1 second
Explanation:
given
w= 4pounds
k(spring constant) = 2lb/ft
g(gravitational constant) = 10m/s² = 32ft/s²
β(initial point above equilibrum) = 1
velocity = 14ft/s
attached is an image showing the calculations, because some of the parameters aren't convenient to type.
If the mass of an object doubles, the weight of the object also doubles
If the mass of an object halves, the weight of the object also halves
Explanation:
The mass of an object is an intrinsec property of the object that gives a measure of the "amount of matter" in the object. Mass is indipendent from the location of the object.
On the contrary, weight gives a measure of the force of gravitational attraction felt by the object in a gravitational field. Weight is dependent on the location.
The mass and the weight of an object are related by the following equation:
where:
W is the weight of the object
m is its mass
g is the acceleration of gravity
We see from the formula that the weight of an object is directly proportional to its mass. This means the following:
- If the mass of an object doubles, the weight of the object also doubles
- If the mass of an object halves, the weight of the object also halves
Learn more about forces and weight:
brainly.com/question/8459017
brainly.com/question/11292757
brainly.com/question/12978926
#LearnwithBrainly
The answer is the diameter of the cam shaft.
This is used to compute for the area of the circle so you can multiply it with the rocker ratio to get maximum amount of weight the valve can lift.
Answer:
the total energy before collision is 12.25J
the total energy after collision is tranfered to sound and heat (by the friction between the two clay balls)
Explanation:
first we should know the velocity of the 2 balls:
momentum=mass ×velocity
we have the momentum and the mass of the 2
so momentum ÷mass=velocity
clay ball 1 velocity=7 m/s & clay ball 2 velocity= -7 m/s
KE=1/2 mv²
1/2 ×0.25×7²=6.125J KE of ball 1
1/2 ×0.25×-7²=6.125J KE of ball 2
add them both we will have 12.25J which is before collision
this energy will then be tranfered to heat and sound as they stop after the collision(velocity =0m/s)
