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krok68 [10]
3 years ago
12

A 9 -slug mass hangs by a rope from the ceiling. Using the standard value of gravitational acceleration g = 32.2 fts 2, what is

the tension in the rope?
Engineering
1 answer:
kap26 [50]3 years ago
3 0

Answer:

For the Mass to hang without falling

It simply means that the Tension that supports the weight force has to be Equal to or greater than it.

T=W

T= mg

m= 9 slugs

g=32.2ft/s².

T= 9 x 32.2

T= 289.8 slug.ft/s².

Or in normal units

1 Slug = 14.59Kg

1ft = 0.3048m

m= 9 slugs = 131.345kg

g =32.2ft/s² = 9.8m/s²

T= 9.8 x 131.345

T= 1,287.18N.

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A plane surface 25 cm wide has its temperature maintained at 80°C. Atmospheric air at 25°C ows parallel to the surface
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Answer:

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3 years ago
The cantilevered W530 x 150 beam shown is subjected to a 9.8-kN force F applied by means of a welded plate at A. Determine the e
snow_lady [41]

The <em>equivalent force-couple system</em> at O is the force and couple experienced when at point O due to the applied force at point A

The <em>equivalent force couple</em> system at O due to force <em>F</em> are;

Force, F =  (<u>8.65·i - 4.6·j</u>) KN

Couple, M₀ ≈ <u>40.9 </u>k kN·m

The reason the above values are correct is as follows:

The known values for the <em>cantilever</em> are;

The <em>height </em>of the beam = 0.65 m

The <em>magnitude of </em>the applied <em>force</em>, F = 9.8 kN

The <em>length </em>of the beam = 4.9 m

The <em>angle </em>away from the vertical the force is applied = 26°

The required parameter:

The <em>equivalent force-couple system</em> at the centroid of the beam cross-section of the cantilever

Solution:

The <em>equivalent force-couple system</em> is the force-couple system that can replace the given force at centroid of the beam cross-section at the cantilever O ;

The <em>equivalent force</em> \overset \longrightarrow F = 9.8 kN × cos(28°)·i - 9.8 kN × sin(28°)·j

Which gives;

The <em>equivalent force</em> \overset \longrightarrow F ≈ (<u>8.65·i - 4.6·j</u>) KN

The <em>couple </em><em>acting </em>at point O due to the force <em>F</em> is given as follows;

The <em>clockwise moment</em> = <em>9.8 kN × cos(28°) × 4.9</em>

The <em>anticlockwise moment</em> = <em>9.8 kN × sin(28°) 0.65/2 </em>

The sum of the moments = Anticlockwise moment - Clockwise moments

∴ The <em>sum </em>of the moments, ∑M, gives the moment acting at point O as follows;

M₀ = <em>9.8 kN × sin(28°) 0.65/2 - 9.8 kN × cos(28°) × 4.9</em>  ≈ 40.9 kN·m

The couple acting at O, due to F,  M₀ ≈ <u>40.9 kN·m</u>

The equivalent force couple system acting at point O due the force, F, is as follows

F =  (8.65·i - 4.6·j) KN

M₀ ≈ <u>40.9 </u>k kN·m

Learn more about equivalent force systems here:

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4 0
3 years ago
The demand schedules for Jones, Smith, and other buyers are shown in the table below:
Solnce55 [7]

The demand curve is the graphical representation of the relationship between the price of a good and the quantity demanded for a given period of time.

<h3>What is a demand schedule?</h3>

A demand schedule is a table which shows the quantity demanded of a good or service at different price levels.

A demand schedule can be graphed as a continuous demand curve on a chart where the Y-axis represents the price and the X-axis represents quantity.

Here, a typical representation, the price will appear on the left vertical axis, the quantity demanded on the horizontal axis.

Note that the complete information wasn't found and an overview was given.

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2 years ago
A circle has an area of 153.86 in squared what’s the radius of the circle
sweet [91]

Answer: 49

Explanation: So, how you figure this out is by taking the area of the circle (153.86) and dividing it by pi (3.14) which equals 49 which is your answer! So, the <u>radius of the circle is </u><u>49</u>.

If you need any further instruction or help let me know!

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