Answer:
0.008
Explanation:
From the question, the parameters given are:
Velocity V = 5 m/s
Pressure = 10 pa
But pressure = F/A
10 = F/A
F = 10A
Substitute all the parameters into the formula below
Coefficient of viscosity (η) = F × r /[AV]
Where
F = tangential force,
r = distance between layers,
A = Area, and
V = velocity
(η) = 10A × 0.004 /[A × 5]
The A will cancel out
(η) = 10 × 0.004 /[5]
(η) = 0.04 /5
(η) = 0.008
Therefore, the coefficient of viscosity of the fluid is 0.008
Answer:
The strength coefficient is K = 591.87 MPa
Explanation:
We can calculate the strength coefficient using the equation that relates the tensile strength with the strain hardening index given by

where Sut is the tensile strength, K is the strength coefficient we need to find and n is the strain hardening index.
Solving for strength coefficient
From the strain hardening equation we can solve for K

And we can replace values

Thus we get that the strength coefficient is K = 591.87 MPa
Answer:
The value of R is 10101
Explanation:
As per the given data
D = 1000100100
G = 100101
Redundant bit = 6-bits - 1-bit = 5-bits
No add fice zero to D
D = 100010010000000
Now calculate R as follow
R = D / G
R = 100010010000000 / 100101
R = 10101
Workings are attached with this question
Explanation:
D the answer is D and anyone can answer this Question
Answer:
C. Signal-to-quantization-noise ratio
Explanation: