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omeli [17]
3 years ago
15

Select the correct answer

Engineering
1 answer:
kifflom [539]3 years ago
5 0

Answer: C. Exchanging ideas with the group will help build his knowledge and reputation

Explanation:

Professional networking refers to the building of professional relationships. This helps in establishing connections that are mutually-beneficial with the people that are in ones profession.

Based on the scenario given, the reason for Vijay to join a networking group is that exchanging ideas with the group will help build his knowledge and reputation.

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Can I have free money? I want to get a new pc
GREYUIT [131]

Answer:

NO!

Explanation:

6 0
3 years ago
Read 2 more answers
CAD(computer-aided design) software and is used in__________and __________that show how to construct an object. Technical drawin
8_murik_8 [283]

Answer:

Plans; blueprints.

Explanation:

In Engineering, it is a common and standard practice to use drawings and models in the design and development of various tools or systems that are being used for proffering solutions to specific problems in different fields such as engineering, medicine, telecommunications and industries.

Hence, a design engineer make use of drawings such as pictorial drawings, sketches, or technical drawing to communicate ideas about a design to others, to record and retain informations (ideas) so that they're not forgotten and to analyze how different components of a design work together.

Technical drawing is mainly implemented with CAD (computer-aided design) software and is typically used in plans and blueprints that show how to construct an object.

Additionally, technical drawings show in detail how the pieces of something (object) relate to each other, as well as accurately illustrating the actual (true) shape and size of an object in the design and development process.

5 0
3 years ago
piston-cylinder assembly contains water vapor, initially at 10 bar and 360 degC. The water undergoes a process where pv=constant
DIA [1.3K]

Answer:

Check the explanation

Explanation:

A diagrams showing the process in p-v and T-s and the Model engineering <u><em>(which is the quest in constructing miniature working representations of proportionally-scaled in full-sized machines. It is a subdivision of metalworking with a sharp importance on artisanry, in contrast to mass production.)</em></u> can be seen in the attached images below.

3 0
3 years ago
- What will happen if high voltage from the HV battery or motor-generator is shorting to frame ground?
Novosadov [1.4K]

Answer:

Unlike a low voltage battery such as 12V, high voltage from a High Voltage battery should not be grounded to the chassis for several numbers of reason which are;

- HV up to 350V have a corresponding high current which generate unwanted magnetic field and causes magnetic interference. This can be reduced by using a twisted conductor so that the interference can be cancelled.

-HV can result to surges which result to spark over and flash over between phase and ground.

5 0
3 years ago
Consider a 1.80-m-tall man standing vertically in water and completely submerged in a pool. Determine the difference between the
defon

Answer:

17.658 kPa

Explanation:

The hydrostatic pressure of a fluid is the weight of a column of that fluid divided by the base of that column.

P = \frac{weight}{base}

Also, the weight of a column is its volume multiplied by it's density and the acceleration of gravity:

weight = \delta * v * g

Meanwhile, the volume of a column is the area of the base multiplied by the height:

V = base * h

Replacing:

P = \frac{\delta * base * h * g}{base}

The base cancels out, so:

P = \delta * h * g

The pressure depends only on the height of the fluid column, the density of the fluid and the gravity.

If you have two point at different heights (or depths in the case of objects submerged in water) each point will have its own column of fluid exerting pressure on it. Since the density of the fluid and the acceleration of gravity are the same for both points (in the case of hydrostatics density is about constant for all points, it is not the case in the atmosphere), we can write:

\Delta P = \rho * g * (h1 - h2)

We do not know at what depth the man of this problem is, but it doesn't matter, because we know the difference in height of the two points of interes (h1 - h2) = 1.8 m. So:

\Delta P = 9.81 \frac{m}{s^{2} } * 1000 \frac{kg}{m^3} * 1.8 m = 17658 Pa = 17.658 kPa

4 0
3 years ago
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