Answer: The temperature of the gas if 65.85g of N2 are placed in 17.5L container with a pressure of 1988 mmHg is 1780. 6° C
Explanation:
The ideal gas law states that the volume, pressure and temperature of the a gas is related to the number of moles.
It is represented thus;
P V = n R T
Parameters :
Pressure, P = 1988 mmHg
Volume, V = 17.5 L
number of moles, n = mass ÷ molar mass
mass of N2 = 65.84g
Molar mass of N2 = 28.02 g/ mol
n = 65.85 ÷ 28.02
n = 2. 350 moles.
Temperature = ?
Universal gas constant, R = 8.314 J/mol. K
Calculations :
T = P V ÷ n R
T = 1988 × 17.5 ÷ 2.350 × 8.314
T = 34790 ÷ 19. 5379
T = 1780. 6 ° C
Thus, the temperature of the gas is 1780. 6 ° C
Answer:
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First question. Applying ideal gas equation PV=nRT, P= 101.3 x 10³Pa = 1atm. therefore, 1 x 260 x 10^-3 = n x 0.082 x 294.( Temperature in kelvin=273+21). n = 0.01 moles. Volume of gas at STP= n x 22.4 = 0.01x22.4 = 0.224L. Hope this helps
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Hope this helps:D
Have a great rest of a brainly day!</span>