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3 years ago

An essay that is 530 words over an experiment. EX. Coke vs Mento Invisible Ink

Chemistry

1 answer:

irga5000 [103]3 years ago

4 0

Answer:

<h2>Coke Zero Case Study Coca Cola is world renowned soft drink. Unfortunately when it comes to taking health into consideration this is one of the last things one should be ingesting into their system.</h2>

Explanation:

WHT

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What does CoH12O6 tell you about the glucose molecule?

Leokris [45]

Answer:

Glucose = C6H12O6

molecular mass = 6(12) + 12(1) + 6(16)

= 72 + 12 + 96

= 180 g

Explanation:

Glucose has a chemical formula of: C6H12O6 That means glucose is made of 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms. ... Glucose is produced during photosynthesis and acts as the fuel for many organisms.

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2 years ago

ASAP PLZ HELP I WILL MARK BRAINLIEST Based on the diagram, what can you conclude about the pole of the magnet? O It is a south p

Vinvika [58]

Answer:C

Explanation:I took the test

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3 years ago

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What are the oxidation numbers of the atoms in this reaction?

ipn [44]

A, B and D should be the ones you should check

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3 years ago

What is the final temperature when 60.2 g of water at 72.4°C is mixed with 20.3 g of water at 34.4°C? (The specific heat of wate

Murljashka [212]

Answer:

72.3 c

Explanation:the celcuis would over power the fairnheight

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2 years ago

Extend the aufbau sequence through an element that has not yet been identified, but whose atoms would completely fill 7p orbital

Thepotemich [5.8K]

Answer:

Number of electrons = 118

Electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶

Explanation:

Given: A chemical element that has completely filled 7p orbital.

According to this, the principal occupied electron shell or the valence shell of such an element is 7p.

⇒ the principal quantum number (n) for the valence shell is 7.

∴ this element belongs to the period 7 of the periodic table.

Also, an element that has completely filled p-orbital belongs to the group 18 of the p-block.

Therefore, an element that belongs to the group 7 and period 18 of the periodic table, should have a completely filled 5f, 6d, 7s and 7p orbitals.

Therefore, the electronic configuration should be: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶

And, the number of electrons = atomic number of radon (Rn) + 14 + 10 + 2 + 6 = 86 + 32 = 118.

Therefore, the given element has atomic number 118 and has the electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶. Thus the given element can be Oganesson.

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3 years ago