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Tanzania [10]
3 years ago
6

11. A roller coaster car is moving slowly up a long ramp to the very top of the roller coaster. It goes over the top and starts

down a steep slope and it picks up speed rapidly as it rolls down an almost vertical slope. Four seconds later, at the bottom of the steep slope, its velocity is 28 m/s. The average acceleration during those 4 seconds was 6 m/s2 . What was the initial velocity of the roller coaster car as it started down the slope?
Physics
1 answer:
DiKsa [7]3 years ago
3 0

Answer:

a = (v2 - v1) / t

a t = v2 - v1

v1 = v2 - a t

v1 = 28 m/s - 6 m/s^2 * 4 s = 4 m/s

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A 100-kg tackler moving at a speed of 2.6 m/s meets head-on (and holds on to) an 92-kg halfback moving at a speed of 5.0 m/s. Pa
DIA [1.3K]

Given that,

Mass of trackler, m₁ = 100 kg

Speed of trackler, u₁ = 2.6 m/s

Mass of halfback, m₂ = 92 kg

Speed of halfback, u₂ = -5 m/s (direction is opposite)

To find,

Mutual speed immediately after the collision.

Solution,

The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{100\times 2.6+92\times (-5)}{(100+92)}\\\\V=-1.04\ m/s

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3 years ago
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butalik [34]
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4 0
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Which is greater the attraction of the earth for 1 kg of aluminum or aluminum or attraction of 1kg of aluminum for the earth?
OleMash [197]
Those forces are exactly equal.

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A system gains 757 kJ757 kJ of heat, resulting in a change in internal energy of the system equal to +176 kJ.+176 kJ. How much w
Alecsey [184]

Answer:

581 kJ, work was done by the system

Explanation:

According to the first law of thermodynamics:

\Delta U = Q-W

where

\Delta U is the change in internal energy of the system

Q is the heat absorbed by the system (positive if absorbed, negative if released)

W is the work done by the system (positive if done by the system, negative if done by the surrounding)

In this problem,

Q=+757 kJ

\Delta U = +176 kJ

Therefore the work done by the system is

W=Q-\Delta U=757 kJ-176 kJ=+581 kJ

And the positive sign means the work is done BY the system.

5 0
3 years ago
If a an object is traveling at a rate of 5 meters per second squared with a force of 10 Newtons, what is the mass of the object?
Svetllana [295]

Answer:

2 kg

Explanation:

Acceleration = 5 m/s^2

Force = 10 N

Force = mass * acceleration

mass = force / acceleration

mass = 10 / 5

mass = 2 kg

8 0
3 years ago
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