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Tanzania [10]
3 years ago
6

11. A roller coaster car is moving slowly up a long ramp to the very top of the roller coaster. It goes over the top and starts

down a steep slope and it picks up speed rapidly as it rolls down an almost vertical slope. Four seconds later, at the bottom of the steep slope, its velocity is 28 m/s. The average acceleration during those 4 seconds was 6 m/s2 . What was the initial velocity of the roller coaster car as it started down the slope?
Physics
1 answer:
DiKsa [7]3 years ago
3 0

Answer:

a = (v2 - v1) / t

a t = v2 - v1

v1 = v2 - a t

v1 = 28 m/s - 6 m/s^2 * 4 s = 4 m/s

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When the dry-bulb reading of a thermometer is 20°C and the wet-bulb reading is 11°C, the relative humidity is approximately
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Answer:

You need to use charts or a calculator to get 56%

Explanation:

3 0
2 years ago
Please help please help
Inessa [10]

Answer: p= m/v so 90kg/.075m^3 = 1,200

2a. .35 m 1.1 m and .015 m

2b. 35 cm x 110 cm x 1.5 cm = 5,775 cm^3 = 57.75 m^3

mass= pv

2700•57.75= 155,925 kg

mass= 155,925 kg

volume= 57.75 m^3

Explanation: physics

6 0
3 years ago
Phobos's Orbit. Phobos orbits Mars at a distance of 9,380 km from the center of the planet and has a period of 0.3189 days. Assu
Elenna [48]

Answer:

Explanation:

The relation between time period of moon in the orbit around a planet can be given by the following relation .

T² = 4 π² R³ / GM

G is gravitational constant , M is mass of the planet , R is radius of the orbit and T is time period of the moon .

Substituting the values in the equation

(.3189 x 24 x 60 x 60 s)²  = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)

759.167 x 10⁶ = 8.25 x 10²⁰ x 39.43 / (6.67 x 10⁻¹¹ x M )

M = .06424  x 10²⁵

= 6.4 x 10²³ kg .

4 0
2 years ago
How does the current in a circuit change if the resistance is doubled? The current is halved. The current is doubled. The curren
Inessa05 [86]

Answer:

The current is halved

Explanation:

The relationship between the current and the resistance is given by Ohm's Law, as follows:

V = IR\\I = \frac{V}{R}

where,

V = Voltage

I = Current

R = Resistance

Therefore, if we double the resistance:

I' = \frac{V}{2R}\\\\I' = \frac{1}{2}I

Hence the correct option is:

<u>The current is halved</u>

7 0
3 years ago
Read 2 more answers
an object is acted on by a drag force with a magnitude that is proportional to the speed. the object accelerates downward at 3.0
Nutka1998 [239]

The terminal speed of the object falling down is 66.67 m/s.

The terminal speed acquired by the body when,

Weight of the body = Drag force of the body

It is given,

Drag force is directly proportional to the speed,

So,

F = CV

Where F is drag force,

V is the speed,

C is the constant,

So, it can be written as C = F/V.

The weight of the body = mg

The weight of the body = 10m

M is the mass and g is the acceleration due to gravity,

The drag force when the speed is 20m/s.

Drag force = ma

a is the acceleration during the drag force which is given to be 3m/s²,

Drag force = 3m

Now we can write,

F₁/V₁ = F₂/V₂

F₁ is the drag force at 20m/s speed.

F₂ is the weight of the body and V₂ is the terminal speed,

Now, it can be written,

3m/20 = 10m/V₂

V₂ = 66.67 m/s.

So, the terminal speed is 66.67m/s.

To know more about terminal speed, visit,

brainly.com/question/14605362

#SPJ4

7 0
1 year ago
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