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3 years ago

Is 1.252525252525 repeating irrational

Mathematics

1 answer:

qaws [65]3 years ago

4 0

Answer: yes

Step-by-step explanation: ghuhuh

huhuhuh

huhuhuhuh

bhbhbhb

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You have a wire that is 38 cm long. you wish to cut it into two pieces. one piece will be bent into the shape of a square. the o

erica [24]

Circumference + perimeter =38
x = circumference of circle
find r in terms of x
2 $\pi$ r=x
r= $\frac{x}{2 \pi }$
Area= $\pi$ r^2
so..
A= $\pi$ ( $\frac{x}{2 \pi }$ )^2
= $\pi$ ( $\frac{x^{2} }{4 \pi ^{2} }$ )
= $\frac{x^{2} }{4 \pi }$

(38-x) is perimeter
then
$\frac{38-x}{4}$
( $\frac{38-x}{4}$ )^2
$\frac{x^{2} }{4 \pi }$ + ( $\frac{38-x}{4}$ )^2
then you graph it and it equals
16.716 cm the circumference of the circle

6 0

3 years ago

Loretta’s income last year was $81,300. She made $56,800 at her salaried job and had additional passive income. If Loretta earne

aalyn [17]

Answer:

Option a. $2,040

Step-by-step explanation:

step 1

To find out the amount of the additional passive income last year, subtract the amount earned at her salaried job from Loretta’s income last year

$\$81,300-\$56,800=\$24,500$

step 2

Divide the additional passive income last year by 12 (number of months in a year)

$\$24,500/12=\$2,041.67$

therefore

approximately $2,400 per month

5 0

2 years ago

Read 2 more answers

What is the result of substituting for y in the bottom equation y=x+3 y=x^2+2x-4

8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

Solution:

Given that,

$y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4 ----- eqn 2$

We have to substitute eqn 1 in eqn 2

$x + 3 = x^2 + 2x - 4$

$\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0$

$\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}$

$x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}$

$x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925$

$Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925$

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0

3 years ago

Miguel Cabrera had a batting average of 0.33 last season.Mike trout had a batting average of 0.326 during the same season. Who h

Vesna [10]

Answer:

Miguel cabrera

Step-by-step explanation:

Given that :

Miguel cabrera's batting average = 0.33

Mike trout's batting average = 0.326

The average for both players was obtained during the same season:

Hence. Comparing their respective averages,

0.33 = 0.330

0.330 > 0.326

Hence, Miguel Cabrera's batting average is higher than that of Mike trout

8 0

2 years ago

Heather has 50 quarters in a jar. She puts 3 more quarters into the jar each

timama [110]

Answer:

50 + 3n = 100

4 0

3 years ago