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Anarel [89]
2 years ago
10

How did bohr propose light was emitted from a material?

Physics
1 answer:
Artemon [7]2 years ago
6 0

Answer:

when an electron made a transition from an outer orbit to one closer to the nucleus

Explanation:

Bohr amended that view of the motion of the planetary electrons to bring the model in line with the regular patterns (spectral series) of light emitted by real hydrogen atoms. ... Light, he proposed, radiated from hydrogen atoms only

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Why does light behave as shown in the image when it passes from air to glass?
Leto [7]
B) Light slows down when it passes into a denser medium. 

5 0
2 years ago
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Make the following conversion. 34.9 cL = _____ hL. 0.349 0.0349 0.00349 349,000
AnnyKZ [126]
Hey there!

Here is your answer:

<u><em>The proper answer to this question is option C "</em></u><span><u><em>0.00349".</em></u>

Reason:

</span><span><u><em>1 L = 100 cL. Or 1 cL = 0.01 L</em></u>

</span><span><u><em>34.9 cL = 34.9 / 100 L = 0.349 L</em></u>

</span><span><u><em> 1 hL = 100 L. 0.349 L = 0.349 / 100 hL = 0.00349 hL</em></u>

<em>Therefore the answer is option C!</em>

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit</span>
4 0
3 years ago
If 20 beats are produced within a single second, which of the following frequencies could possibly be held by two sound waves tr
zhuklara [117]

The correct choice is

D. 22 Hz and 42 Hz.

In fact, the beat frequency is given by the difference between the frequencies of the two waves:

f_B = |f_1 -f_2|

In this problem, the beat frequency is f_B=20 Hz, therefore the only pair of frequencies that gives a difference equal to 20 Hz is

D. 22 Hz and 42 Hz.

4 0
3 years ago
Read 2 more answers
How high can a 40 N force move a load, when 395 J of work is done?
Juliette [100K]

Answer:

9.875

Explanation:

w=f×s

395=40×s

make s the subject of the formula

s=395/40

=9.875

7 0
3 years ago
Which statement is true for a car that first goes around a curve of radius r at a constant speed v, and then goes around the sam
sasho [114]
Centripetal force is equal to (mv^2)/r
The way I use to answer these question is to set every variable to 1
m=1
v=1
r=1
so centripetal force =1
then change the variable we're looking at
and since we're find when it's half we could either change it to 1/2 or 2, but 2 is easier to use
m=1
v=2
r=1
((1)×(2)^2)/1=4
So the velocity in the 1st part is half the velocity in the 2nd part and the centripetal force is 4× less
The answer is the centripetal force is 1/4 as big the second time around
3 0
3 years ago
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