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adelina 88 [10]
3 years ago
5

2) A 0.4kg ball moves in horizontal circle of radius 3 m at speed of 100m/s. What

Physics
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Answer:

F = 1300 N

Explanation:

F = mv²/R = 0.4(100²)/3 = 1333.3333...

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A laboratory technician drops a 72.0 g sample of unknown solid material, at a temperature of 80.0°C, into a calorimeter. The cal
Natalija [7]

Answer : The specific heat of unknown sample is, 8748.78J/kg^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-[q_2+q_3]

m_1\times c_1\times (T_f-T_1)=-[m_2\times c_2\times (T_f-T_2)+m_3\times c_3\times (T_f-T_2)]

where,

c_1 = specific heat of unknown sample = ?

c_2 = specific heat of water = 4186J/kg^oC

c_3 = specific heat of copper = 390J/kg^oC

m_1 = mass of unknown sample = 72.0 g  = 0.072 kg

m_2 = mass of water = 203 g  = 0.203 kg

m_2 = mass of copper = 187 g  = 0.187 kg

T_f = final temperature of calorimeter = 39.4^oC

T_1 = initial temperature of unknown sample = 80.0^oC

T_2 = initial temperature of water and copper = 11.0^oC

Now put all the given values in the above formula, we get

0.072kg\times c_1\times (39.4-80.0)^oC=-[(0.203kg\times 4186J/kg^oC\times (39.4-11.0)^oC)+(0.187kg\times 390J/kg^oC\times (39.4-11.0)^oC)]

c_1=8748.78J/kg^oC

Therefore, the specific heat of unknown sample is, 8748.78J/kg^oC

7 0
3 years ago
Calculate the velocity of a car that travelled 120km in 2 hours<br>​
Naddik [55]
I need context poggg
5 0
3 years ago
In 450 BCE, Greek philosopher Democritus first thought of the existence of tiny particles that compose everything around us. He
Masja [62]

B. The meaning of 'atomos' according to Democritus in 450 BCE is indivisible.

<h3>The building block of every matter</h3>

A Greek philosopher  known as Democritus first thought of the existence of tiny particles that compose everything around us.

Democritus of Abdera, named the building blocks of matter atomos, meaning literally “indivisible.

Thus, the meaning of 'atomos' according to Democritus in 450 BCE is indivisible.

Learn more about atoms here: brainly.com/question/6258301

#SPJ1

5 0
2 years ago
A uniform, thin rod of length L and mass M is allowed to pivot about its end. The rotational inertia of a rod about its end is M
weeeeeb [17]

Answer:

g = \frac{V_B^2}{L}  =  \frac{\Delta y}{\Delta x}

Explanation:

Given that :

length of the thin rod = L

mass = m

The rotational inertia I = \frac{ML^2}{3}

The experimental design that the student can use to conduct the experimental value of g can be determined as follow:

Taking the integral value of I

I =\int\limits \  r^2  \, dm

where :

\lambda = \frac{m}{L} \\ \\ m = L \lambda \\\\ \lambda dr = dm

I =\int\limits^L_0 { \lambda r^2 } \, dr

I = \frac{\lambda r^3}{3} |^L___0

I = \frac{m}{3 L}L^3

I = \frac{1}{3 }mL^2

k_f = \mu___0}}} = \frac{1}2} I \omega^2

where:

V_B = \omega L

\omega = \frac{V_B}{L}

Equating: \frac{1}2} I \omega^2 = mg \frac{L}{2}; we have:

\frac{1}{2} (\frac{1}{3}mL^2)\frac{V_B^2}{L^2} = mg \frac{L}{2}

V_B^2 = 3gL     since m = 3g

where :

V_B^2 =vertical axis on the graph

L = horizontal axis

V_B^2 = 3gL     ( y = mx)

3g = \frac{V_B^2}{L}

g = \frac{V_B^2}{L}  =  \frac{\Delta y}{\Delta x}

7 0
4 years ago
A convex mirror of focal length 34 cm forms an image of a soda bottle at a distance of 18 cm behind the mirror. The height of th
Mademuasel [1]
<h2>Answers:</h2>

In convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object .

<h2 /><h2>a) Position of the soda bottle (the object) </h2><h2 />

The Mirror equation is:

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}   (1)

Where:

f is the focal distance

u is the distance between the object and the mirror  

v is the distance between the image and the mirror

 

We already know the values of f and v, let's find u from (1):

u=\frac{v.f}{v-f}   (2)

Taking into account the explanation at the beginign of this asnswer:

f=-34cm and v=-18cm

The <u>negative signs</u> indicate the <u>focal distance</u> and the <u>distance between the image and the mirror are virtual </u>

Then:

u=\frac{(-18cm)(-34cm)}{-18cm-(-34cm)}  

u=38.25cm (3) >>>>Position of the soda bottle

<h2>b) magnification of the image </h2><h2 />

The magnification m of the image is given by:

m=-\frac{v}{u} (4)

m=-\frac{(-18cm)}{38.25cm}  

m=0.47 (5)>>>the image is 0.47 smaller than the object

<h2>The fact that this value is positive means the image is upright </h2>

<h2>c) Describe the image </h2><h2 />

According to the explanations and results obtained in the prior answers, the correct option is 9:

<h2>The image is <u>virtual, upright, smaller</u> than the object </h2><h2 /><h2>d) Height of the soda bottle (object) </h2>

Another way to find the magnification is by the following formula:

m=\frac{h_{i}}{h_{o}} (6)

Where:

h_{i} is the image height

h_{o} is the object height

We already know the values of m and h_{i}, let's find h_{o}:

h_{o}=\frac{h_{i}}{m} (7)

h_{o}=\frac{6.8cm}{0.47}  

h_{o}=14.46cm (8) >>>height of thesoda bottle

6 0
3 years ago
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