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Olenka [21]
3 years ago
10

What is the amount of moles for 12.0 g Ar?

Chemistry
2 answers:
Digiron [165]3 years ago
8 0

if i am correct it shall be 12. because i am thinking, 1 mole = 1 ar.

Ainat [17]3 years ago
4 0

Answer:

1 mole is equal to 1 moles Argon, or 39.948 grams

Explanation:

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How much heat is needed warm 65.34 g of water from 18.43 to 21.75
BaLLatris [955]

Given that  

Mass of water = 65.34 g

Amount of heat = mass of water * specific heat (temperature change

)

= 65.34 g * 4.184 J / g-C ( 21.75-18.43 )C

= 907.63  J  

= 0.908 KJ

And  

1 cal = 4.186798 J

907.63 J * 1 cal / 4.186798 J =216.78  cal

Or0.218 kcal  


5 0
3 years ago
The predominant greenhouse gas produced by human use of fossil fuels is __________. View Available Hint(s) The predominant green
mario62 [17]

Answer:

carbon dioxide

Explanation:

Carbon dioxide -

The gas carbon dioxide has a molecular formula of CO₂ ,

During the burning process of the fossil fuels , carbon dioxide is resealed in numerous amount , which act as a greenhouse gas .

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6 0
2 years ago
If 3.0 liters of 0.50 m nacl (aq) is mixed with 9.0 liters of 0.2777 m nacl (aq), what is the final concentration of the resulti
Svetradugi [14.3K]
First, we shall calculate the total number of moles present in the final solution.
Number of moles in 0.50 m NaCl = molarity * volume = 0.50 * 3.0 = 1.5 moles.
Number of moles in 0.2777m NaCl = molarity * volume = 0.2777 * 9.0 = 0.24993 moles
Total number of moles = 1.5 + 0.24993 = 1.74993 moles

Second, we shall calculate the total volume of the final solution.
Total volume = 3 + 9 = 12 litres.

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3 0
3 years ago
Suppose that 2.14 grams of H2SO4 is mixed with enough water to make 225 mL of solution. Determine the Molarity (M) of the soluti
Alik [6]

Answer:

0.0970 M

Explanation:

Remember this equation:

mol/M x V

Convert it so that you can get M.

M=mol/V

Convert the 2.14 grams of H2SO4 into mols

=0.0218

Convert mL to L

225/1000

=0.225

Plug it in.

0.0218/0.225

=0.0970 M

6 0
3 years ago
Calculate the volume in dm3 occupied by 26.4 g of carbon dioxide​
Mama L [17]
  • Density of carbon dioxide=1564kg/m^3
  • Mass=26.4g=0.0264kg

\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}

\\ \sf\longmapsto Volume=\dfrac{Mass}{Density}

\\ \sf\longmapsto Volume=\dfrac{0.0264}{1564}

\\ \sf\longmapsto Volume=1.687m^3=1.69m^3

  • 1m^3=1000dm^3

\\ \sf\longmapsto Volume=1.69(1000)=1690dm^3

7 0
2 years ago
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