2x + 5 ≤ 9x - 14 helppp
1 answer:
You might be interested in
A. It's a composite function, so basically, wherever you see a p, replace it with 5t, because we are given that information. So, your answer is:
![A[p(t)] = 5t \pi 2=10t \pi](https://tex.z-dn.net/?f=A%5Bp%28t%29%5D%20%3D%205t%20%5Cpi%202%3D10t%20%5Cpi%20)
B. Let's use the function we created, and just plug in 2 for t:
![A[p(2)] = 10(2) \pi](https://tex.z-dn.net/?f=A%5Bp%282%29%5D%20%20%3D%2010%282%29%20%5Cpi%20)
![A[p(2)] = 62.83](https://tex.z-dn.net/?f=A%5Bp%282%29%5D%20%3D%2062.83)
So, your answer is (approximately) 62.83 units².
B. Let's use the function we created, and just plug in 2 for t:
So, your answer is (approximately) 62.83 units².
