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2 years ago

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Physics

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taurus [48]2 years ago

5 0

A the endocrine system does not fulfill its function

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A wire has a length of 0.50 m and measures about 0.50 mm in its cross-sectional radius. At normal temperature, what is its resis

miv72 [106K]

Answer:

Explanation:

For resistance , the expression is as follows .

R = ρ L / S where ρ is specific resistance , L is length of wire and S is cross sectional area .

cross sectional area = π x ( .5 x 10⁻³ )²

S = .785 x 10⁻⁶ m²

Putting the values

R = 2.82 x 10⁻⁸ x .50 / .785 x 10⁻⁶

= 1.796 x 10⁻² ohm .

4 0

2 years ago

Which temperature scale does NOT have negative values?

german

Kelvin temperature scale

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2 years ago

A circular loop of wire with a radius of 15.0cm and oriented in the horizontal xy-plane is located in a region of uniform magnet

Drupady [299]

Answer:

See answer

Explanation:

The area of the circular loop is given by:

$A = \pi r^2$

The magnetic flux is given by:

$\phi = \int \vec{B} \cdot d\vec{A}$

$d\vec{A}$ is parallel to $\vec{B}$ and $\vec{B}$ is constant in magnitude and direction therefore:

$\phi = \int \vec{B} \cdot d\vec{A}= \int BdAcos(0)= B\int dA= B*(\pi r^2)= \pi Br^2$

Part A)

initially the flux is $\phi =\pi B r^2$

after the interval $\Delta t= 2.4 [m/s]$

the flux is

$\phi = 0$

now, the EMF is defined as:

$\epsilon =- \frac{d \phi}{dt}$ ,

if we consider $\Delta t= 2.4 [m/s]$ very small then we can re-write it as:

$\epsilon =- \frac{\Delta \phi}{\Delta t}$

$\Delta \phi = 0 - \pi B r^2=-\pi (1.7) (0.15)^2=-0.12$

then:

$\epsilon =- \frac{-0.12}{0.0024} = 50 [V]$

Part B)

When looked down from above, the current flows counter clockwise, according to the right hand rule, if you place your thumb upwards (the direction of the magnetic field) and close your fingers, then the current will flow in the direction of your fingers.

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3 years ago

37 Questions - All Questions Are Required

ANTONII [103]

Acceleration = vf-vi /t
10-22/3=2.6m/s^2

5 0

3 years ago

Read 2 more answers

how much energy is required to move a 4.00-microcoulomb charge through a potential difference of 36.0 volts?

musickatia [10]

Answer:

All you gotta do is search it up. ask the same question you asked on here, type it into google, it'll teach you a lot more than your actual teachers.