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storchak [24]
3 years ago
5

Eva makes a graphic organizer to compare electromagnets with solenoids. A venn diagram with 2 intersecting circles. The circle o

n the left is labeled electromagnet and the circle on the right is labeled solenoid. There is an X in the electromagnet circle. Which description belongs in the region marked X? has a magnetic field like a bar magnet has a metal core uses electromagnetic induction uses an electric current.
Physics
1 answer:
Eva8 [605]3 years ago
5 0

The metalcore is the central component of any metal that is covered by wires. Metalcore is found in the X denoted area.

<h3>What is a solenoid?</h3>

A solenoid is a coil of wire that conducts an electric current. A solenoid is an electromagnet made out of a wire or helical coil.

When an electric current is sent through the coil, it produces a magnetic field. A solenoid is a coil that generates a magnetic field when an electric current passes through it.

When a conductive wire is used to build a loop, a solenoid is formed.

Hence the metalcore is found in the given X area.

To learn more about the solenoid refer to the link ;

brainly.com/question/16015159

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Answer:

k=694.44

Explanation:

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5=1/2k(.0144)

divide both sides by .0144

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How much work is required to lift a 10-newton weight from 4.0 meters to 40 meters above the surface of Earth?
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<h3>Answer : 360J</h3>

<h3>Way to do : </h3>

s = 40m - 4m = 36m

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<h3>A bit of explanation : </h3>

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A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp
lubasha [3.4K]

Answer:

a) 915 m

b) 0.15 W/m^{2}

Explanation:

solution:

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λ=\frac{c}{f}=\frac{3*10^{8} }{12*10^{9}}=0.025 m

the circular radar antenna acts like a circular aperture of diameter D will have a bright central maximum of diameter:

w=2.44λL/D

so at 30 km screen:

w=2.44λL/w

  =2.44*0.025*30*10^3/2

  =915 m

b)

The area of a beam at 30 km is:

A=\pi  r^{2}=\pi (\frac{w}{2} )^2=\pi (\frac{915}{2} )^2=657*10^{3} m^{2}

the average microwave intensity is equal to the ratio of the power of the antenna and area of the beam:

I=P/A

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I=100*10^3/657*10^3

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