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ella [17]
3 years ago
14

Constraints of a crane​

Chemistry
1 answer:
UNO [17]3 years ago
4 0

Answer:

The crane should have an electromagnet attached to its arm. The electromagnet: should have a soft iron core made from a bundle of short lengths of iron wire, must be strong enough to pick up several steel paperclips, nails or coins. Work on your own. This task will be assessed.

Explanation:

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Calculate the pressure in torr that a 0.44 g sample of carbon dioxide gas would exert at a temperature of 46.2 C when it occupie
svlad2 [7]

Answer: 0.052torr

Explanation: Please see attachment for explanation

7 0
3 years ago
Ideal He gas expanded at constant pressure of 3 atm until its volume was increased from 9 liters to 15 liters. During this proce
kkurt [141]

Explanation:

The given data is as follows.

             P = 3 atm

                = 3 atm \times \frac{1.01325 \times 10^{5} Pa}{1 atm}  

                 = 3.03975 \times 10^{5} Pa

    V_{1} = 9 L = 9 \times 10^{-3} m^{3}    (as 1 L = 0.001 m^{3}),  

        V_{2} = 15 L = 15 \times 10^{-3} m^{3}

            Heat energy = 800 J

As relation between work, pressure and change in volume is as follows.

                  W = P \times \Delta V

or,                W = P \times (V_{2} - V_{1})

Therefore, putting the given values into the above formula as follows.

                  W = P \times (V_{2} - V_{1})

                      = 3.03975 \times 10^{5} Pa \times (15 \times 10^{-3} m^{3} - 9 \times 10^{-3} m^{3})

                      = 1823.85 Nm

or,                   = 1823.85 J

As internal energy of the gas \Delta E is as follows.

                     \Delta E = Q - W

                                  = 800 J - 1823.85 J

                                  = -1023.85 J

Thus, we can conclude that the internal energy change of the given gas is -1023.85 J.

8 0
3 years ago
Calculate the missing variables in each experiment below using Avogadro’s law.
blagie [28]

Answer:

The answer to your question is: letter c

Explanation:

Data

V1 = 612 ml    n1 = 9.11 mol

V2 = 123 ml    n2 = ?

Formula

                               \frac{V1}{n1}  =  \frac{V2}{n2}

                                         n2 = \frac{n1V2}{V1}

                                         n2 = \frac{(9.11)((123)}{(612)}

                                                n2 = 1.83 mol                                                

5 0
3 years ago
If calcium has two valence electrons and sulfur has six, how many calcium atoms are needed to form an ionic bond with sulfur?
Kipish [7]
3 calcium atoms would be needed.
3 0
3 years ago
Read 2 more answers
Rank the following atoms by number of valence electrons. Rank from most to fewest valence electrons. To rank items as equivalent
Fed [463]

To count the number of valence electrons we look at the electronic configuration and add the electrons form the electronic shell with the highest principal quantum number.

Rb: [Kr] 5s¹ - 1 valence electron

Xe: [Kr] 5s² 4d¹⁰ 5p⁶ - 8 valence electrons

Sb: [Kr] 5s² 4d¹⁰ 5p³ - 5 valence electrons

I:    [Kr] 5s² 4d¹⁰ 5p⁵ - 7 valence electrons

In:  [Kr] 5s² 4d¹⁰ 5p¹ - 3 valence electrons

Rank from most to fewest valence electrons:

Xe > I > Sb > In > Rb

6 0
3 years ago
Read 2 more answers
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