Answer: 21.3 g of 
are required to make 0.30 L of 0.500 M .
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
moles of = 
Now put all the given values in the formula of molality, we get
Therefore, 21.3 g of are required to make 0.30 L of 0.500 M .
Answer:
<h2>The gas pressure will remain the same until the number particles remain in the range of multiple of avagadro number.</h2>
Explanation:
It will remain same until the avagadro number is achieved as the gass less than avagadro number (1 mole) will occupy same volume as the the multiple of avagadro number ( mole).
If gas is less than 1 mole it will occupy same volume as that of 1 mole.... If the number of particles are increased than the 1 mole. The gas occupy more volume consequently the pressure will be increased.
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Mass of MnO2 = 25 g
The reaction would be 3MnO2 + 4Al --> 3Mn(s) + 2Al2O3
Molar mass of Al = 26.982 g/mol
Molar mass of MnO2 = 54.938 + 2(15.999) = 86.936 g/mol
Calculating the moles = 25 / 86.936 = 0.2876 mol.
Mole ratio MnO2 and Al considering the equation = 3 mol of MnO : 4 mol of Al
Calculating the moles of Al = 0.2876 mol MnO2 x (4 mol of Al / 3 mol of MnO)
Number of moles of Al = 0.3834
Getting the mass in grams as asked = 0.3834 mol x 26.982 g/mol = 10.34 grams.
We get white fumes of Amonium Chloride.
HCL + NH3 gives NH4CL + H2
