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Anon25 [30]
3 years ago
9

10 pointsss Where are tsunamis likely to originate?

Chemistry
2 answers:
Brrunno [24]3 years ago
8 0

Answer:

Pacific Ocean

Explanation:

ycow [4]3 years ago
6 0
Tsunamis are likely to originate in the pacific ocean
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2) The pH of 1x10-1M (HNO3) solution is:<br><br> A)1<br> B) 1.3<br> C)5<br> D)2
nikdorinn [45]

Concentration of H+ ions in HNO3 solution is 10⁻¹ which is equal to 0.1 M

\bf  \: pH \:  =  - log[{h}^{ + }]

putting the value we get

\sf \dashrightarrow  \: pH \:  =  - log \: [ \frac{1}{10}] \\  \\ \sf \dashrightarrow  \: pH \: =   - log \: {10}^{ - 1}  \\  \\ \sf \dashrightarrow  \: pH \: = 1

So, the required option is A) 1

8 0
2 years ago
7. If you constructed graphs, what trends do they indicate in your data?
lisabon 2012 [21]
A tend line I believe (I am going off the other guy cause they are right.)
4 0
3 years ago
A 80.0 g piece of metal at 88.0°C is placed in 125 g of water at 20.0°C contained in a calorimeter. The metal and water come to
grandymaker [24]

Answer:

The specific heat of the metal is 0.485 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of the piece of metal = 80.0 grams

Mass of the water = 125 grams

Initial temperature of the metal = 88.0 °C

Initial temperature of water =20.0 °C

Final temperature = 24.7 °C

pecific heat of water is 4.18 J/g*°C

<u>Step 2:</u> Calculate specific heat of the metal

Qgained = -Qlost

Q =m*c*ΔT

Qwater = - Qmetal

m(water)*c(water)*ΔT(water) = -m(metal)*c(metal)*ΔT(metal)

with mass of water = 125 grams

with c( water) = 4.18 J/g°C

with ΔT(water) = T2-T1 = 24.7 - 20 = 4.7°C

with mass of metal = 80.0 grams

with c(metal) = TO BE DETERMINED

with ΔT(metal) = 24.7 - 88.0 = -63.3 °C

125*4.18*4.7 = -80 * C(metal) * -63.3

2455.75 = -80 * C(metal) * -63.3

C(metal) = 2455.75 / (-80*-63.3)

C(metal) = 0.485 J/g°C

The specific heat of the metal is 0.485 J/g°C

3 0
3 years ago
Do free electrons appear anywhere in the balanced equation for a redox reaction?
Andru [333]

Yes, free electrons appear in balanced redox reaction equations. However, this is only true for half-reactions. This is because redox reactions primarily involve the transfer of electrons, which are better visualized if explicitly shown in the balanced reactions. In reduction reactions, electrons are placed on the left side of the equation. Oxidation reactions show electrons on the right side of the equation.


Explanation:

A half reaction is either the chemical reaction or reduction reaction part of an oxidoreduction reaction. A half reaction is obtained by considering the amendment in chemical reaction states of individual substances concerned within the oxidoreduction reaction. Half-reactions are usually used as a way of leveling oxidoreduction reactions.The half-reaction on the anode, wherever chemical reaction happens, is Zn(s) = Zn2+ (aq) + (2e-).

The metal loses 2 electrons to create Zn2+. The half-reaction on the cathode wherever reduction happens is Cu2+ (aq) + 2e- = Cu(s).

Here, the copper ions gain electrons and become solid copper.

4 0
3 years ago
Read 2 more answers
3,621.471 in scientific notation?
tiny-mole [99]
That would be 3.621471•10^3
3 0
3 years ago
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