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Novay_Z [31]
2 years ago
5

What is the molar mass of Al2(SO4)3

Chemistry
2 answers:
Goshia [24]2 years ago
8 0
Molar mass= <span>342.15 g/mol</span>
andrey2020 [161]2 years ago
4 0

Answer:

341.97 g/mol

Explanation:

Let us first write down the relative atomic masses of all the elements involved. (Please not that these will differ from periodic table to periodic table. Familiarize yourself with the data sheet in your institution)

Al - 26.892

S - 32.066

O - 15.999

From the formula we can see that we

Two aluminium atoms = 26.892*2 = 53.784

Three sulphur atoms = 32.066*3 = 96.198

Twelve oxygen atoms  = 191.988

Add them all up = 341.97

So the molar mass is 341.97 g/mol. The units have to assigned because this is the molar mass. Relative molecular mass has not units

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a diatomic element has six bonding electrons, six non-bonding electrons, and 2 anti-bonding electrons. what is the bond order? g
Deffense [45]

The bond order of a diatomic element with  six bonding electrons, six non-bonding electrons, and 2 anti-bonding electrons is 2 whose formula is( bonding electrons-anti bonding electrons)/2.

<h3>What is an element?</h3>

An element  is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.

Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.

The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with same atomic number are atoms of same element.

Learn more about element,here:

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7 0
1 year ago
Read 2 more answers
Will bromine react with sodium and why?
Archy [21]

<span><span>When you write down the electronic configuration of bromine and sodium, you get this

Na:
Br: </span></span>

<span><span />So here we the know the valence electrons for each;</span>

<span><span>Na:  (2e)
Br:  (7e, you don't count for the d orbitals)

Then, once you know this, you can deduce how many bonds each can do and you discover that bromine can do one bond since he has one electron missing in his p orbital, but that weirdly, since the s orbital of sodium is full and thus, should not make any bond.

However, it is possible for sodium to come in an excited state in wich he will have sent one of its electrons on an higher shell to have this valence configuration:</span></span>

<span><span /></span><span><span>

</span>where here now it has two lonely valence electrons, one on the s and the other on the p, so that it can do a total of two bonds.</span><span>That's why bromine and sodium can form </span>

<span>
</span>

4 0
3 years ago
Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low
LenaWriter [7]

Answer:

Compound B has greater molar mass.

Explanation:

The depression in freezing point is given by ;

\Delta T_f=i\times k_f\times m..[1]

m=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in kg}}

Where:

i = van't Hoff factor

k_f = Molal depression constant

m = molality of the solution

According to question , solution with 5.00 g of A in 100.0 grams of water froze at at lower temperature than solution with 5.00 g of B in 100.0 grams of water.

The depression in freezing point of solution with A solute: \Delta T_{f,A}

Molar mass of A = M_A

The depression in freezing point of solution with B solute: \Delta T_{f,B}

Molar mass of B = M_B

\Delta T_{f,A}>\Delta T_{f,B}

As we can see in [1] , that depression in freezing point is inversely related to molar mass of the solute.

\Delta T_f\propto \frac{1}{\text{Molar mass of solute}}

M_A

This means compound B has greater molar mass than compound A,

4 0
3 years ago
A Variable That Stays The Same In An Experiment Is A ?
hammer [34]
The variable that stays the same in an experiment is called the controlled variable

Hope this helps
3 0
2 years ago
Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution.
Alenkinab [10]

Answer:

a. Rate = k [H2O+-OH][Br-]

Explanation:

For a reaction:

nA+xB→C+D

The rate of the reaction is:

Rate = [A]ⁿ[B]ˣ

Now, in a mechanism, the rate of the reaction depends of the slow step. In the problem:

H2O+-OH + Br-→ HOBr + H2O

And the rate is:

<h3>a. Rate = k [H2O+-OH][Br-] </h3>

5 0
2 years ago
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