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Ksenya-84 [330]
3 years ago
13

The density of mercury is 13.5g/mL. What is the volume of this liquid if the sample weighs 12.5 pounds?

Chemistry
1 answer:
Mama L [17]3 years ago
7 0

Answer : The volume of liquid is 420 mL.

Explanation :

Density : The mass per unit volume of a substance is known as density.

Formula used:

\text{Density}=\frac{\text{Mass}}{\text{Volume}}

As we are given:

Density of mercury = 13.5 g/mL

Mass = 12.5 pounds

First we have to convert mass of sample from pound to gram.

Conversion used:

As, 1 pound = 453.6 g

So, 12.5 pounds = 453.6 × 12.5 g = 5670 g

Now we have to calculate the volume of liquid.

\text{Density}=\frac{\text{Mass}}{\text{Volume}}

Now putting all the given values in this formula, we get:

13.5g/mL=\frac{5670g}{\text{Volume}}

Volume = 420 mL

Therefore, the volume of liquid is 420 mL.

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If a gas is initially at a pressure of nine ATM and a volume at 21 L at a temperature of 253K and the pressure is raise to 15 AT
Tom [10]

Answer:

15.0L

Explanation:

p/v = constan

(9*21)/253 =(15v)/ 302

v = (9*21*302)/(15*253)

v=15.0

3 0
3 years ago
10 moles of carbon dioxide has a mass of 440 g. What is the relative formula mass of carbon dioxide?
Ksenya-84 [330]

Answer: 44g

Explanation: The formular for finding Moles is ;

Moles =  Mass / Molar Mass or Formular Mass.

Base on this question; Moles = 10, Mass = 440g, and Formular Mass = ?

Making 'Formular Mass', subject of the formular; we thus have;

Formular mass = Mass / Moles = 440/ 10 = 44g

7 0
2 years ago
. A standard dry cell has an output voltage of A. 1.5 VDC. B. 1.1 VDC. C. 1.2 VDC. D. 2.0 VDC.
NikAS [45]
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4 0
2 years ago
What is molarity of 47.0 g KCl dissolved in enough water to give 375 mL of solution?
natita [175]

This question provides us –

  • Weight of \bf  KCl is = 47 g
  • Volume, V = 375 mL

__________________________________________

  • Molar Mass of \bf   KCl –

\qquad \twoheadrightarrow\bf  39.0983 \times 35.453

\qquad \twoheadrightarrow\bf 74.5513

<u>Using formula</u> –

\qquad \purple{\twoheadrightarrow\bf Molarity _{(Solution)} =  \dfrac{ W\times 1000}{MV}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{ 47 \times 1000}{74.5513\times 375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{47000}{27956.7375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \cancel{\dfrac{47000}{27956.7375}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = 1.68117M

\qquad \pink{\twoheadrightarrow\bf Molarity _{(Solution)}  = 1.7M}

  • Henceforth, Molarity of the solution is = 1.7M

___________________________________________

6 0
2 years ago
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