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3 years ago

11

Which of the following statements is true for a synthesis reaction? A single product is formed. Multiple products are formed. A

single reactant breaks down. Multiple reactants break down.

2 answers:

pychu [463]3 years ago

8 0

Answer : The correct option is, A single product is formed.

Explanation :

Synthesis reaction : It is defined as the chemical reaction in which the multiple substances or the reactants combines then it forms a single product.

The synthesis reaction is represented as,

$X+Y\rightarrow XY$

For example : When the hydrogen gas react with oxygen gas then its forms water as a single product.

The balanced chemical reaction will be :

$2H_2+O_2\rightarrow 2H_2O$

Decomposition reaction : It is defined as a type of reaction in which a single larger compound decomposes to give two or more or multiple smaller molecules as a product.

The general representation of decomposition reaction is :

$AB\rightarrow A+B$

For example : When nitrogen dioxide decomposes then it gives oxygen gas and nitrogen gas as a products.

$2NO_2\rightarrow 2O_2+N_2$

Hence, the true statements for a synthesis reaction is, a single product is formed.

Papessa [141]3 years ago

4 0

Answer: A single product is formed.

Explanation: Synthesis reaction is one in which two or more substances react together to form a single product.

$N_2+3H_2\rightarrow 2NH_3$

A reaction in which a single reactant breaks down to form two or more than two products is called as decomposition.

$CaCO_3\rightarrow CaO+CO_2$

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A solution of 6.2 M H2SO4 is diluted from 2.0 L to 3.0 L. What is the molarity of the resulting solution?

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3 years ago

During an experiment, 95 grams of calcium carbonate reacted with an excess amount of hydrochloric acid. If the percent yield of

almond37 [142]

Answer:

Actual yield: 86.5 grams.

Explanation:

How many moles of formula units in 95 grams of calcium carbonate $\rm CaCO_3$ ?

Refer to a modern periodic table for relative atomic mass data:

Ca: 40.078;
C: 12.011;
O: 15.999.

Formula mass of $\rm CaCO_3$ :

$M(\mathrm{CaCO_3}) = \underbrace{1\times 40.078}_{\rm Ca} + \underbrace{1\times 12.011}_{\rm C} + \underbrace{3\times 15.999}_{\rm O} = \rm 100.086\;g\cdot mol^{-1}$ .

$\displaystyle n(\mathrm{CaCO_3}) = \frac{m(\mathrm{CaCO_3})}{M(\mathrm{CaCO_3})} = \rm \frac{95\;g}{100.086\;g\cdot mol^{-1}} = 0.949184\;mol$ .

How many moles of $\rm CaCl_2$ will be produced?

The coefficient in front of $\rm CaCO_3$ in the chemical equation is the same as that in front of $\rm CaCl_2$ . That is:

$\displaystyle \frac{n(\rm CaCl_2)}{n(\rm CaCO_3)} = 1$ .

$\displaystyle n(\mathrm{CaCl_2}) = n(\mathrm{CaCO_3})\cdot \frac{n(\rm CaCl_2)}{n(\rm CaCO_3)} = n(\mathrm{CaCO_3}) = \rm 0.949184\;mol$ .

What's the theoretical yield of calcium chloride? In other words, what's the mass of $\rm 0.949184\;mol$ of $\rm CaCl_2$ ?

Again, refer to a periodic table for relative atomic data:

Ca: 40.078;
Cl: 35.45.

$M(\mathrm{CaCl_2}) = \underbrace{1\times 40.078}_{\rm Ca} + \underbrace{2\times 35.45}_{\rm Cl} = \rm 110.978\;g\cdot mol^{-1}$ .

$\begin{aligned}m(\mathrm{CaCl_2}) &= n(\mathrm{CaCl_2})\cdot M(\mathrm{CaCl_2})\\ &= \rm 0.949184\;mol\times 110.978\;g\cdot mol^{-1}\\ &= \rm 105.339\; g\end{aligned}$ .

What's the actual yield of calcium chloride?

$\displaystyle \text{Percentage Yield} = \frac{\text{Actual Yield}}{\text{Theoretical Yield}}\times 100\%$ .

$\displaystyle \begin{aligned}\text{Actual Yield} &= \text{Theoretical Yield}\cdot \frac{\text{Percentage Yield}}{100\%}\\ &=\rm 105.339\; g \times \frac{82.15\%}{100\%}\\&= \rm 86.5\;g \end{aligned}$ .

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4 years ago

Write a net ionic equation for the reaction between mno4- and fe2+ in acid solution

dedylja [7]

Answer : The complete net ionic reaction between $MnO _{4} ^{-}$ and $Fe ^{2+}$ in an acid solution, can be written as :-

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3 years ago

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there is no d electron that can be promoted via the absorption of visible light

Explanation:

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The colours of transition metal compounds stem from d-d transition of electrons due to the presence of vacant d orbitals of appropriate energy to which electrons could be promoted.

For elements whose atoms have a d10 configuration, such vacant orbitals does not exist hence their compounds are not colored.

Sometimes, the colour of transition metal compounds stem from ligand to metal charge transfer(LMCT) for instance in KMnO4.

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