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4 years ago

Which term describes the reaction process in a fission reaction?

2 answers:

7 0

The answer is chain reaction. In fission, you are breaking atoms down. You need to keep breaking them down with neutrons. They do it over and over and again, hitting each other after one hits the other.

Drupady [299]4 years ago

3 0

A for plato -chain reaction

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Bromine water can be used to distinguish between these two molecules?? true or false

Tom [10]

Answer:i dkd

Explanation:

jsach

4 0

3 years ago

Olympic cyclist fill their tires with helium to make them lighter. Calculate the mass of air in an air filled tire and the mass

inn [45]

Answer: The mass difference between the two is 7.38 grams.

Explanation:

To calculate the number of moles, we use the equation given by ideal gas follows:

$PV=nRT$

where,

P = pressure = 125 psi = 8.50 atm (Conversion factor: 1 atm = 14.7 psi)

V = Volume = 855 mL = 0.855 L (Conversion factor: 1 L = 1000 mL)

T = Temperature = $25^oC=[25+273]K=298K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$8.50atm\times 0.855L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{8.50\times 0.855}{0.0821\times 298}=0.297mol$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For air:

Moles of air = 0.297 moles

Average molar mass of air = 28.8 g/mol

Putting values in equation 1, we get:

$0.297mol=\frac{\text{Mass of air}}{28.8g/mol}\\\\\text{Mass of air}=(0.297mol\times 28.8g/mol)=8.56g$

Mass of air, $m_1$ = 8.56 g

For helium gas:

Moles of helium = 0.297 moles

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

$0.297mol=\frac{\text{Mass of helium}}{4g/mol}\\\\\text{Mass of helium}=(0.297mol\times 4g/mol)=1.18g$

Mass of helium, $m_2$ = 1.18 g

Calculating the mass difference between the two:

$\Delta m=m_1-m_2$

$\Delta m=(8.56-1.18)g=7.38g$

Hence, the mass difference between the two is 7.38 grams.

5 0

3 years ago

assuming gasoline can be represented as C8H18, how much oxygen is needed to completely burn this fuel. answer in grams of oxygen

aleksandrvk [35]

Answer:

3.51 g of oxygen per gram of gasoline is required.

Explanation:

Solution:

First of all we will write the balance chemical equation.

C8H18 + 12.5O2 → 8CO2 + 9H2O

This equation shows that,

1 mole of gasoline react with 12.5 mole of oxygen for complete burning.

mass of one mole of gasoline = 8×12 + 18×1 = 114 g

mass of 12.5 mole of oxygen = 12.5 (16×2) = 400 g

Formula:

mass of oxygen per gram of gasoline = (400 / 114) = 3.51

so, 3.51 g of oxygen require for per gram of gasoline.

5 0

4 years ago

What is the acceleration of a car that goes from 50km/hour to 90 km/hour in 5 seconds?

BartSMP [9]

Answer:

the acceleration i think is 8

Explanation:

50+5x8

6 0

3 years ago

Which quantity could best be measured with a meter stick?

Ilya [14]

Answer:

Explanation:

A meter stick measures distances ( like centimeters) so....B

it does NOT measure mass , volume or VERY large distances (Like earth's diameter)

3 0

2 years ago

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