Explanation:
Let acceleration due to Gravity for a planet is given by:

Here,
Escape velocity is given by:

Here,  
 
and g_X = 2g
Therefore,
 
        
             
        
        
        
Answer:
20.25 m
Explanation:
- <u>Centripetal acceleration </u>is given by; the square of the velocity, divided by the radius of the circular path.
That is;
          <em><u>ac = v²/r</u></em>
<em>         </em><em><u> Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the  radius, m</u></em>
Therefore; 
r = v²/ac
   = 27²/36 
   = 20.25 m
Hence the radius is 20.25 meters
 
        
                    
             
        
        
        
Rutherford's experiment<span> utilized positively charged alpha particles (He with a +2 charge) which were deflected by the dense inner mass (nucleus). The conclusion that could be formed from this result was that </span>atoms<span> had an inner core which contained most of the mass of an </span>atom<span> and was positively charged.</span>
        
             
        
        
        
Answer:
2.8 cm
Explanation:
 = Separation between two first order diffraction minima = 1.4 cm
 = Separation between two first order diffraction minima = 1.4 cm
D = Distance of screen = 1.2 m
m = Order
Fringe width is given by

Fringe width is also given by

For second order

Distance between two second order minima is given by


The distance between the two second order minima is 2.8 cm