Answer:
34.6g
Explanation:
Given parameters:
Mass of Octane = 11.2g
Reaction expression;
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
Mass of octane = 11.2g
Unknown:
Mass of carbon dioxide produced = ?
Solution:
From the balanced reaction equation;
2 mole of octane produced 16 moles of carbon dioxide
From the given specie, let us find the number of moles;
Number of moles =
Molar mass of C₈H₁₈ = 8(12) + 18(1) = 114g/mole
Number of moles of octane =
= 0.098mole
2 mole of octane produced 16 moles of carbon dioxide
0.098 mole of octane will produce
= 0.79mole of CO₂
Mass of CO₂ = number of moles x molar mass
Molar mass of CO₂ = 12 + 2(16) = 44g/mol
Mass of CO₂ = 0.79 x 44 = 34.6g
Question 5)
1 Hour: 100g
40 Minutes: 50g
20 Minutes: 25g
0 Minutes: 12.5g
Question 6)
160 Days: 80ou
120 Days: 40ou
80 Days: 20ou
40 Days: 10ou
0 Days: 5ou
Every period of time, the radioactive isotopes halve in numbers as they emit radiation.
I think you now know the gist. Try doing the rest yourself.
Good luck.
Answer:
On the basis of this explanation, if the rate of lactate production is high enough, the cellular proton buffering capacity can be exceeded, resulting in a decrease in cellular pH. These biochemical events have been termed lactic acidosis. ... Every time ATP is broken down to ADP and Pi, a proton is released
Explanation:
Answer:
1520mmHg
Explanation:
Data obtained from the question include:
V1 (initial volume) = 600 mL
P1 (initial pressure) = 760 mmHg
V2 (final volume) = 300 mL
P2 (final pressure) =.?
Using the Boyle's law equation P1V1 = P2V2, the final pressure of the gas can easily be obtained as shown below:
P1V1 = P2V2
760 x 600 = P2 x 300
Divide both side by 300
P2 = (760 x 600) /300
P2 = 1520mmHg
The final pressure of the gas is 1520mmHg
Answer:
s = d÷ t
Explanation:
Where s means speed, d means distance and t means time