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marusya05 [52]
3 years ago
12

How many moles of aluminum metal are needed to produce 3.33 moles of aluminum chloride?

Chemistry
1 answer:
Ugo [173]3 years ago
4 0

There are 2 moles of aluminum metal that is needed to produce 3.33 moles of aluminum chloride

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hi, help me please with both number 4 and 5, please be sure of your answer, first to answer gets brainliest!​
Evgesh-ka [11]

Answer:

4. mutualism

5. commensalism

Explanation:

4. mutualism (they benefit off each other)

5. commensalism (the whale is unaffected)

8 0
2 years ago
How many moles of hydrogen are in the sample?<br> Round your answer to 4 significant digits.
finlep [7]

Answer:

1.56 mol H₂

Explanation:

Mg₃(Si₂O₅)₂(OH)₂

<em>There are 4 Si moles per Mg₃(Si₂O₅)₂(OH)₂ mol</em>. With that in mind we can <u>calculate how many Mg₃(Si₂O₅)₂(OH)₂ moles are there in the sample</u>, using the <em>given number of silicon moles</em>:

  • 3.120 mol Si * \frac{1molMg_3(Si_2O_5)_2(OH)_2}{4molSi} = 0.78 mol Mg₃(Si₂O₅)₂(OH)₂

Then we can <u>convert Mg₃(Si₂O₅)₂(OH)₂ moles into hydrogen moles</u>, keeping in mind that <em>there are 2 hydrogen moles per Mg₃(Si₂O₅)₂(OH)₂ mol</em>:

  • 0.78 mol Mg₃(Si₂O₅)₂(OH)₂ * 2 = 1.56 mol H₂
8 0
3 years ago
What volume of a 3.0 M stock solution of H2SO4 is needed to prepare 2.8 L of a 1.6 M H2SO4 solution?
Georgia [21]
Use M1V1 = M2V2 to solve
3(V1) = 2.8 * 1.6
3(V1) = 4.48
V1 = 1.493 L of stock solution
4 0
3 years ago
Read 2 more answers
A chemist must dilute 34.3mL of 1.72mM aqueous calcium sulfate solution until the concentration falls to 1.00mM. He'll do this b
EastWind [94]

Answer:

58.9mL

Explanation:

Given parameters:

Initial volume  = 34.3mL    = 0.0343dm³

Initial concentration  = 1.72mM   = 1.72 x 10⁻³moldm⁻³

Final concentration  = 1.00mM = 1 x 10⁻³ moldm⁻³

Unknown:

Final volume  =?

Solution:

Often times, the concentration of a standard solution may have to be diluted to a lower one by adding distilled water. To find the find the final volume, we must recognize that the number of moles of the substance in initial and final solutions are the same.

   Therefore;

              C₁V₁  =  C₂V₂

where C and V are concentration and 1 and 2 are initial and final states.

        now input the variables;

                      1.72 x 10⁻³ x  0.0343 = 1 x 10⁻³  x V₂

                        V₂ = 0.0589dm³ = 58.9mL

         

4 0
3 years ago
Which characteristic would you predict from a solution that has a pH of 5?
AlexFokin [52]
With a pH of five, it would mean that this substance is a weak acid one would also it expect it would be sour.
4 0
3 years ago
Read 2 more answers
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