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VMariaS [17]
3 years ago
13

2 points 3. True or False. Near Earth's equator, we do NOT see vast differences in seasons or temperature changes because the an

gle of light/energy in this area does NOT change much. * O True O False​
Chemistry
1 answer:
SpyIntel [72]3 years ago
6 0
The answer is false. there is still temperature changes and different seasons. hope this helps< 3
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Use the solubility curve above to answer the following: If I add 130 g of potassium iodide to 100 g of water at 10°C, how would
zhenek [66]
<span>solution of KI becomes saturated at 10 degrees when around 135-138g KI are added to 100 g of water, so it should be still unsaturated, A. unsaturated (although it is very close to saturation)</span>
7 0
3 years ago
Which type of formula represents the simplest whole-number ratio of atoms of the elements in a compound?
sleet_krkn [62]
The empirical formula represents the simplest whole number shows the simplest whole number ratio of atoms in a compound.  An example of this is the empirical formula for glucose (C₆H₁₂O₆) is C₃H₆O₃.  

I hope this helps.  Let me know if anything is unclear.
5 0
3 years ago
A solution contains an unknown amount of dissolved magnesium. Addition of
Scrat [10]

Taking into account the reaction stoichiometry, 2.13 grams of magnesium was dissolved in the solution.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Mg²⁺(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2 Na⁺(aq)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Mg²⁺: 1 mole
  • Na₂CO₃: 1  mole
  • MgCO₃: 1 mole
  • Na⁺: 2 moles

The molar mass of the compounds is:

  • Mg²⁺: 24.3 g/mole
  • Na₂CO₃: 106 g/mole
  • MgCO₃: 84.3 g/mole
  • Na⁺: 23 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Mg²⁺: 1 mole ×24.3 g/mole= 24.3 grams
  • Na₂CO₃: 1 mole ×106 g/mole= 106 grams
  • MgCO₃: 1 mole ×84.3 g/mole=84.3 grams
  • Na⁺: 2 moles ×23 g/mole= 46 grams

<h3>Mass of magnesium dissolved</h3>

The following rule of three can be applied: If by reaction stoichiometry 1 mole of Na₂CO₃ react with 24.3 grams of magnesium, 0.0877 moles of Na₂CO₃ react with how much mass of magnesium?

mass of magnesium=\frac{0.0877 moles of Na_{2}C O_{3}x24.3 grams of magnesium }{1 mole of Na_{2}C O_{3}}

<u><em>mass of magnesium= 2.13 grams</em></u>

Finally, 2.13 grams of magnesium was dissolved in the solution.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

4 0
3 years ago
Proportional tax<br> regressive tax<br> progressive tax
Crazy boy [7]

I am sorry can you explain it more?

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In a pedigree, when a circle of square is halfway shaded, is it
exis [7]
Ummm I think it is C. ( not sure)
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