Answer:
The percent composition of fluorine is 65.67%
Explanation:
Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.
That is, the percentage composition is the percentage by mass of each of the elements present in a compound.
The calculation of the percentage composition of an element is made by:
In this case, the percent composition of fluorine is:
percent composition of fluorine= 65.67%
<u><em>The percent composition of fluorine is 65.67%</em></u>
Answer:
They decrease, because of the stronger effective nuclear charge.
Explanation:
- Atomic radii decreases from left to right across a period.
- This is due to the increase in the no. of protons and electrons through the period.
- One proton has a greater effect than one electron.
- So, electrons are attracted towards the nucleus and resulting in a smaller atomic radii.
<em>Thus, the right choice is: They decrease, because of the stronger effective nuclear charge.</em>
<em></em>
Answer:
1.63 × 10²⁴ atoms.
Explanation:
To calculate the number of atoms (N) contained in 2.7moles of carbon, we multiply the number of moles (n) by Avogadro's number (6.02 × 10²³).
That is, N = n × nA
Where;
N = number of atoms
n = number of moles (mol)
nA = Avogadro's numbe
N = 2.7 × 6.02 × 10²³
N = 16.254 × 10²³
N = 1.63 × 10²⁴ atoms.
Hence, there are 1.63 × 10²⁴ atoms in 2.7moles of Carbon.
The element Sodium (Na) has 11 protons and 1 valence electron.
Answer:
as u should. candy ain't even that tempting >^<
