Answer:
False
Explanation:
Some animals are cold blooded
A) Picture D
B) Chlorine
C) Natrium chloride (NaCl) / salt
The weak acid will have fewer ions than the strong acid of similar concentration.
The chemical reactions for a weak acid and a strong acid is given below:
- Strong acid: HA → H⁺ + A⁻
- Weak acid: HA ⇆ H⁺ + A⁻
<h3>What are strong and weak acids?</h3>
Strong acids are acids which dissociate completely in solutions. Examples of strong acids are hydrochloric acid and sulfuric acid.
Weak acids are acids which dissociate only partially in solutions. Examples of weak acids are carbonic acid and acetic acid.
Weak acids of a similar concentration to a strong acid have fewer hydrogen ions.
The equation of the dissociation of strong acids and weak acids are given below:
- Strong acid: HA → H⁺ + A⁻
- Weak acid: HA ⇆ H⁺ + A⁻
In conclusion, weak acids produce few ions in solution while strong acids fully dissociate into ions in solution.
Learn more about strong and weak acids at: brainly.com/question/15192126
#SPJ1
It is the top level or the tertiary consumer.
Answer:
1-butene
Explanation:
In this case, the problem is already stating and saying the reaction involved here.
1-bromobutane undergoes a dehydrohalogenation in presence of a base. This will cause an elimination reaction forming a product.
As this is an elimination product, this can be done in two ways.
The first way is with an unimolecular reaction where the halide is eliminated from the starting reactant in a two step reaction involving a carbocation formation. This is known as E1 reaction. However, the conditions for this reaction is to be in acid medium.
The second way is with a bimolecular reaction where the halide is eliminated from the starting reactant in just one step, and no carbocation is formed. This is known as E2 reaction and is commonly used with bases.
In the case of this problem, we are undergoing an E2 reaction, therefore, the mechanism of reaction is just one step, and when this happens, the base substract the hydrogen from Carbon 2, eliminates the bromide and forms a double bond, giving the 1-butene.
You can see the mechanism in the following picture.
Hope this helps