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ICE Princess25 [194]
3 years ago
10

Which statement describes how technology has increased our information on Mars?

Chemistry
2 answers:
elena-s [515]3 years ago
6 0

Answer:

The correct statements are that the Curiosity rover found sulfur compound in rocks, and detected carbon in organic molecules.

Explanation:

The Curiosity rover detected methane gas in the atmosphere of Mars as well as organic substances from shallow-soil samples from Gale crater. Both the soil compounds and methane gas are organic matter. The organic matter is chemically illustrated as combinations of hydrogen, carbon, and other elements basically witnessed in biology like oxygen and sulfur, that is, usually related to life.  

At certain times, the rocks can get produced on their own via the geological procedures. However, discovering organic matter in such large concentration indicates that it potentially exhibit biological origins, either from bacteria or other life forms, which prevailed long ago.  

Luden [163]3 years ago
4 0

The Curiosity rover found sulfur compounds in rocks and carbon in organic compounds like propane, butene, benzene, toluene and thiophene.

It detected methane, not in soil samples, but in the Martian atmosphere.

It did not discover helium in underground pockets. The hole it can drill is only 5 cm deep.

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12.23 g of ammonia (NH3) are dissolved in enough water to make 560.0 mL of solution. How many moles of NH3 are added to the wate
Karolina [17]

Answer:

0.719 moles of NH₃

Explanation:

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Mass of amonia = 12.23 g

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3 years ago
If a 45 mM phosphate solution(solution A) had an absorbance of 1.012. What would be the absorbance if 11 mL of solution A was us
timofeeve [1]

Answer:

0.550

Explanation:

The absorbance (A) of a substance depends on its concentration (c) according to Beer-Lambert law.

A = ε . <em>l</em> . c

where,

ε: absorptivity of the species

<em>l</em>: optical path length

A 45 mM phosphate solution (solution A) had an absorbance of 1.012.

A = ε . <em>l</em> . c

1.012 = ε . <em>l</em> . 45 mM

ε . <em>l</em>  = 0.022 mM⁻¹

We can find the concentration of the second solution using the dilution rule.

C₁ . V₁ = C₂ . V₂

45mM . 11mL = C₂ . 20.0 mL

C₂ = 25 mM

The absorbance of the second solution is:

A = (ε . <em>l</em> ). c

A = (0.022 mM⁻¹) . 25 mM = 0.55 (rounding off to 3 significant figures = 0.550)

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Answer:

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Explanation:

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