I believe its 10^23 u r saying
then no. of moles= 9.03*10^23/6.02*10^23=1.5mole
Answer:
f = 1.09 × 10¹⁵ Hz
Explanation:
Given data:
Frequency of wave = ?
Wavelength of wave = 2.73 ×10⁻⁷ m
Solution:
Formula:
Speed of light = frequency × wavelength
speed of light = 3× 10⁸ m/s
by putting values,
3× 10⁸ m/s = f × 2.73 ×10⁻⁷ m
f = 3× 10⁸ m/s / 2.73 ×10⁻⁷ m
f = 1.09 × 10¹⁵s⁻¹
s⁻¹ = Hz
f = 1.09 × 10¹⁵ Hz
write an equation to represent the oxidation of an alcohol.
identify the reagents that may be used to oxidize a given alcohol.
identify the specific reagent that is used to oxidize primary alcohols to aldehydes rather than to carboxylic acids.
identify the product formed from the oxidation of a given alcohol with a specified oxidizing agent.
identify the alcohol needed to prepare a given aldehyde, ketone or carboxylic acid by simple oxidation.
write a mechanism for the oxidation of an alcohol using a chromium(VI) reagent.
The reading mentions that pyridinium chlorochromate (PCC) is a milder version of chromic acid that is suitable for converting a primary alcohol into an aldehyde without oxidizing it all the way to a carboxylic acid. This reagent is being replaced in laboratories by Dess‑Martin periodinane (DMP), which has several practical advantages over PCC, such as producing higher yields and requiring less rigorous reaction conditions. DMP is named after Daniel Dess and James Martin, who developed it in 1983.
This page looks at the oxidation of alcohols using acidified sodium or potassium dichromate(VI) solution. This reaction is used to make aldehydes, ketones and carboxylic acids, and as a way of distinguishing between primary, secondary and tertiary alcohols.
Oxidizing the different types of alcohols
The oxidizing agent used in these reactions is normally a solution of sodium or potassium dichromate(VI) acidified with dilute sulfuric acid. If oxidation occurs, the orange solution containing the dichromate(VI) ions is reduced to a green solution containing chromium(III) ions. The electron-half-equation for this reaction is
Cr2O2−7+14H++6e−→2Cr3++7H2O
Answer:
Follows are the explanation to this question:
Explanation:
When the drug is negatively charged, its negative electrolyte is annihilated to just the positive electrode. It is enticed, and it may not have a picture showing the electrode, however, We suppose that electrodes from either side of a skin slice. Its negative electrode will bypass or push thru the skin if in front of the counter terminal this becomes a red-positive electrode.
Answer:
Thx Have a Fantastic day :)
Explanation:
