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3 years ago

PLS HELP!!!!! 30 POINTS!!!!

Chemistry

2 answers:

katen-ka-za [31]3 years ago

8 0

Answer:

The picture is not there

Lapatulllka [165]3 years ago

5 0

Answer:

1. accurate but not precise

2. precise but not accurate

3. accurate and precise

4. neither

Explanation:

hope this helps :)

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Explain why 5.00 grams of salt does not contain the same number of particles as 5.0 grams of sugar

Tom [10]

Answer:

5.00 grams of salt contain more particles than 5.0 grams of sugar

Explanation:

Salt = NaCl

Molar mass = 58.45 g/mol

Sugar = C₁₂H₂₂O₁₁

Molar mass = 342.3 g/mol

Sugar's molar mass is higher than salt.

So 1 mol of sugar weighs more than 1 mol of salt

But 5 grams of salt occupies more mole than 5 grams of sugar

5 grams of salt = 5g / 58.45 g/m = 0.085 moles

5 grams of sugar = 5g/ 342.3 g/m = 0.014 moles

In conclusion, we have more moles of salt in 5 grams; therefore there are more particles than in 5 g of sugar.

3 0

3 years ago

Someone pls help me With this I will make you as brain

RoseWind [281]

The answer to that question is c

5 0

2 years ago

Two liquids – one polar, one nonpolar – have the same molar mass. which one has the higher boiling point?

Anton [14]

Polar will always have the higher boiling point because they have strong van der waal forces

7 0

3 years ago

(2 pts) The solubility of InF3 is 4.0 x 10-2 g/100 mL. a) What is the Ksp? Include the chemical equation and Ksp expression. MW

Aleonysh [2.5K]

Answer:

a) Ksp = 7.9x10⁻¹⁰

b) Solubility is 6.31x10⁻⁶M

Explanation:

a) InF₃ in water produce:

InF₃ ⇄ In⁺³ + 3F⁻

And Ksp is defined as:

Ksp = [In⁺³] [F⁻]³

4.0x10⁻²g / 100mL of InF₃ are:

4.0x10⁻²g / 100mL ₓ (1mol / 172g) ₓ (100mL / 0.1L) = 2.3x10⁻³M InF₃. Thus:

[In⁺³] = 2.3x10⁻³M InF₃ × (1 mol In⁺³ / mol InF₃) = 2.3x10⁻³M In⁺³

[F⁻] = 2.3x10⁻³M InF₃ × (3 mol F⁻ / mol InF₃) = 7.0x10⁻³M F⁻

Replacing these values in Ksp formula:

Ksp = [2.3x10⁻³M In⁺³] × [7.0x10⁻³M F⁻]³ = 7.9x10⁻¹⁰

b) 0.05 moles of F⁻ produce solubility of InF₃ decrease to:

7.9x10⁻¹⁰ = [x] [0.05 + 3x]³

Where x are moles of In⁺³ produced from solid InF₃ and 3x are moles of F⁻ produced from the same source. That means x is solubility in mol / L

Solving from x:

x = -0.018 → False solution, there is no negative concentrations.

x = 6.31x10⁻⁶M → Right answer.

Thus, solubility is 6.31x10⁻⁶M

3 0

3 years ago

Using the systematic approach for equilibrium problems, calculate the pH of 0.05 M HOCl. Ka= 3.0*10-8 Group of answer choices 3.

SVEN [57.7K]

Answer:

The pH is equal to 4.41

Explanation:

Since HClO is a weak acid, its dissociation in aqueous medium is:

HClO ⇄ ClO- + H+

start: 0.05 0 0

change -x +x +x

balance 0.05-x x x

As it is a weak acid it dissociates very little, in its ClO- and H + ions, so the change is negative, where x is a degree of dissociation.

the acidity constant when equilibrium is reached is equal to:

$Ka=\frac{[ClO-]*[H+]}{[HClO]}=\frac{x*x}{0.05-x}=3x10^{-8}$

The 0.05-x fraction can be approximated to 0.05, because the ionized fraction (x) is very small, therefore we have:

$3x10^{-8}=\frac{x^{2} }{0.05}$

clearing the x and calculating its value we have:

$x=3.87x10^{-5}=[H+]=[ClO-]$

the pH can be calculated by:

$pH=-log[H+]=-log[3.87x10^{-5}]=4.41$

7 0

3 years ago