Answer:
% comp. H = 2.8%, % comp. Cl = 97.2%
Explanation:
HCl mass = mass of H + mass of Cl
HCL mass = 1.00794 + 35.453 = 36.46094
% comp. of H = 1.007694 / 36.46094 x 100 = around 2.8% (2.76376308455)
% comp. of Cl = 35.453 / 36.46094 x 100 = around 97.2% (97.2355622208)
It can be represented by atom -9
It would be Fluorine in real..
Answer:

Explanation:
Hello!
In this case, since the reaction between hydrogen and oxygen to produce water is:

When equal masses of each reactant go in contact to carry out the reaction, we can identify the maximum mass of yielded water as the fewest mass yielded by each reactant, just as shown below:

Thus, since hydrogen yields more water than real, we limit the maximum mass of water to those 55.2 g yielded by oxygen as hydrogen would be in excess.
Best regards!
<em>Answer:</em>
<h2>
<em>4</em><em>9</em><em>/</em><em>3</em><em>0</em></h2>
<em>Solution</em><em>,</em>
<em>Reciprocal</em><em> </em><em>of </em><em>6</em><em>/</em><em>1</em><em>1</em><em>=</em><em>1</em><em>1</em><em>/</em><em>6</em>
<em>Now,</em>
<em>-</em><em>1</em><em>/</em><em>5</em><em>+</em><em>1</em><em>1</em><em>/</em><em>6</em>
<em>=</em><em>-</em><em>1</em><em>*</em><em>6</em><em>+</em><em>1</em><em>1</em><em>*</em><em>5</em><em>/</em><em>3</em><em>0</em>
<em>=</em><em>-</em><em>6</em><em>+</em><em>5</em><em>5</em><em>/</em><em>3</em><em>0</em>
<em>=</em><em>4</em><em>9</em><em>/</em><em>3</em><em>0</em>
<em>Hope </em><em>it</em><em> helps</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>