1) Balanced chemical equation
H2SO4 + 2NaOH ---> Na2 SO4 + 2H2O
=> 1 mol H2SO4 : 2 moles NaOH
2) Convert 89.3 g of H2SO4 and 96.0 g of NaOH to moles
Molar mass of H2SO4 = 98.1 g/mol
Molar mass of NaOH = 40.0 g/mol
moles = mass in grams / molar mass
moles H2SO4 = 89.3 g / 98.1 g/mol = 0.910 mol
moles NaOH = 96.0 g / 40.0 g/mol = 2.40 mol
3) Theoretical molar ratio = 2 moles NaOH / 1 mol H2SO4
So, all the 0.91 mol of H2SO4 will be consumed along with 1.820 (2*0.91) moles of NaOH, and 0.580 moles (2.40 - 1.82) of NaOH will be left over by the chemical reaction.
4) Convert 0.580 moles NaOH to mass
0.580 moles * 40.0 g/mol = 23.2 g of NaOH will be left over
Hey there!
I believe the answer is Combination (or Synthesis) Reaction.
At room temperature hydrogen chloride is a colorless gas with a sharp or pungent odor. Under pressure or at temperatures below –85°C (-121°F), it is a clear liquid.
