The correct option is (C) 6.02 X 10²³
A sample of CH₄O with a mass of 32.0 g contains <u>6.02 X 10²³</u> molecules of CH₄O.
To calculate the number of moles;
Molar mass of CH₄O = C + 4(H) + O
= 12.01 + 4(1.008) + 16
= 32.04 g/mol
So, 1 mol of CH₄O = 32.04 g of CH₄O
Given, 32.0 g of CH₄O
According to Avagadro's constant 1 mole of a substance contains 6.022× 10^23 particles (molecules, atoms or ions).
= (32.0 g/1)(1 mol CH₄O/32.04 g CH₄O)(6.02x10²³/1 mol CH₄O)
= 6.02 X 10²³ molecules of CH₄O
Hence, a sample of will contain number of molecules 6.02 X 10²³ molecules.
Learn more about the Moles calculation with the help of the given link:
brainly.com/question/21085277
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Answer:True
Explanation: An anion has a larger radius than a neutral atom because it gains valence electrons. There are added electron/electron repulsions in the valence shell that expand the size of the electron cloud, which results in a larger radius for the anion.
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