Answer:
true b and c
Explanation:
n the electromechanical transitions of the atoms the relationship must be fulfilled
= R (1 / nf - 1 / no²)
where for the final state nf = 1 giving in the case of hydrogen the Lymma series whose smallest wavelength is lam = 122 nm with nf = 1 and there are a series of spectral lines for each value of n of the final state
in the case of sodium so well it has a transition from an excited state to the kiss state (bad)
Now let's review the different proposals
a) False. The electronic potential for sodium is much lower than for hydrognosia
b) True
c) True
d) true
█ Question <span>█
</span><span>In an electronic transition, an atom cannot emit what?
</span>█ Answer █
When an electronic transition is occurring, an atom cannot emit ultra-violet light.
<span>Hope that helps! ★ <span>If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia</span></span>
Answer:
the circuit must be closed
Explanation: