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lubasha [3.4K]
3 years ago
11

How many grams of Al(OH)3 are produced from 3.00 g of AlCl3 with excess of NaOH?

Chemistry
1 answer:
Blizzard [7]3 years ago
3 0

Answer:

1.772 gram is the approximate answer

Explanation:

molecular mass of AlCl3 is 132 g per mole and of Al(OH)3 is 78 g per mole

the reaction is

AlCl3 + 3 NaOH ---> Al(OH)3 + 3 NaCl

from the reaction it is clear that 1 mole AlCl3 makes 1 mole Al(OH)3

implies 132g AlCl3 gives 78g Al(OH)3

Implies 3g AlCl3 gives

3*122/78 = 1.772 grams

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A. The half-life for a first order reaction in 49 minutes. What is the rate constant?B.For a second order reaction, the half-lif
Burka [1]

Answer:

a) 0,014 min⁻¹

b) 1452 seconds.

c) 0,02156 M

d) The faster rate is for the reaction A. The largest rate constant, k, is for A reaction

Explanation:

a) For a first order reaction the half-life is:

t_{1/2} = \frac{ln(2)}{k} <em>(1) </em>As half.life is 49 min. Rate constant -k- is: 0,014 min⁻¹

b) The half-life is defined as the time that takes in descompose the half of the initial concentration of a compound.

As half-life is 726s. In 726s the concentration will be 0,300M, In the next 726s the concentration will be 0,150M. Thus, thae time it takes to decrease concentration until 0,150M is 726s×2= 1452 seconds

c) In the same way, 11072 years are 4 half-life for this reaction, thus:

0,345M/2⁴ = 0,02156 M

d) By definition of half-life, the less half-life, the faster rate. Thus, The faster rate is for the reaction A.

By (1) half-life is inversely proportional to rate constant. Thus, the less half-life, the largest rate constant. The largest rate constant, k, is for A reaction

I hope it helps!

7 0
3 years ago
5. State the change in energy required to break the bonds in a water<br> molecule.
Lorico [155]

Answer:

I’m not for sure

Explanation:

8 0
3 years ago
How many moles are in 5.67x10^24 atoms of RbCl?
Mademuasel [1]

Answer:

<h2>9.42 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{5.67 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 9.418604...

We have the final answer as

<h3>9.42 moles</h3>

Hope this helps you

4 0
3 years ago
The lighter elements of Group I and II have distinctly different chemistry from their heavier congeners. For example, Be and Li
marishachu [46]

Answer:

Answer:

Explanation:

(A) Heavier members of group 1A are usually more reactive than the lighter members e.g. lithium react very slowly with liquid bromine whereas CS  react violently.

Similarly Be of group 2A has smaller size, heavier member of this group show different colour in flame test but Be and Mg emit light when heated. Reactivity of group 2A metals decreases down the group

(B) In ethylene polymerization, the stronger catalytic action is shown by the alkyl of metal having less diameter e.g Be, Li etc.

A lithium alkyl in a hydrocarbon solvent is stereospecific catalyst for polymerisation of isoprene

7 0
3 years ago
Explain why a cool flame is important in heating a solution to dryness
mario62 [17]
Hot flames have a tendency to make problem and as the there is evaporation of solution it infrequently gets overheated and the fluid progresses toward becoming super heated. That regularly makes "bumping" in which the problem area ejects and that is probably going to scatter any solid and on the off chance that you are doing quantitative work that implies the trial is demolished and if not at least it will be a mess, that is why cool flames are important to use instead of hot flames.
5 0
3 years ago
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