It is important because if the sample size is smaller, outliers could skew the data more than if it was large.
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Answer:
9.7 x 10⁻⁴
Explanation:
HA ⇄ H⁺ + A⁻
C(eq) 0.0174 10⁻²·³⁹ 10⁻²·³⁹
=0.0041M =0.0041M
Ka = [H⁺][A⁻]/[HA] = (0.0014)²/(0.0174) = 9.7 x 10⁻⁴
The standard temperature and pressure is 273 K and 1 atm. Since, pressure is not changed we can use Charle's law for the calculations.
<span>Charle's law says "at a constant pressure, the volume of a fixed amount
of gas is directly proportional to its absolute temperature".
V α T
Where V is the volume and T is the temperature
in Kelvin of the gas. We can use this for two situations as,
V</span>₁/T₁ = V₂/T₂<span>
</span>V₁ =
806 mL<span>
T</span>₁ =
26 ⁰C = 299 K
V₂ <span>=
? </span><span>
T</span>₂ =
273 K<span>
<span>
By applying the
formula,
</span></span>(806 mL / 299 K) = (V₂ / 273 K)
V₂ = 735. 91 mL
<span>
Hence, the answer is "a".</span>
