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3 years ago

Can swords shatter from cold temperatures

1 answer:

6 0

Depends on how the sword is made, what materials are used and temperature used but yes they can shatter.

When molecules cool down they stop vibrating and moving as much and so they "shrink" and the metal of the sword becomes brittle. sometimes they shrink at different phases which cause tension in the sword if this tension is strong enough it can cause the metallic bonds to break causing the sword to shatter.

hope that helps

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3 years ago

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A mixture of CO2 and Kr weighs 35.0 g and exerts a pressure of 0.708 atm in its container. Since Kr is expensive, you wish to re

ollegr [7]

Explanation:

Since, it is given that carbon dioxide is completely removed by absorption with NaOH. And, pressure inside the container is 0.250 atm.

For Kr = 0.250 atm and pressure $CO_{2}$ will be calculated as follows.

$CO_{2}$ = (0.708 - 0.250) atm

= 0.458 atm

Now, we will calculate the mole fraction as follows.

$CO_{2} = \frac{0.458}{0.708}$

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$CO_{2} = 0.646 \times 44$

= 28.424

Kr = $0.353 \times 83.78$

= 29.57

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Total mass = (28.424 + 29.57)

= 57.994

Hence, the percentage of $CO_{2}$ and Kr are calculated as follows.

$CO_{2} = \frac{28.424}{57.99} \times 100$

= 49%

Kr = $\frac{29.57}{57.99} \times 100$

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3 years ago

The concentration of grain alcohol (C2H5OH) in whisky is given in "degrees proof", which is twice the percent alcohol by volume

andrew-mc [135]

The mole fraction and molality of alcohol, C₂H₅OH, in 85°proof vodka is 0.186 and 12.70 mol/kg respectively.

<h3>Data provided:</h3>

Molality = moles of solute/kilogram of solvent
Mole fraction = number of moles of solute/ total number of moles
Density = mass/volume
number of moles = mass/molar mass
molar mass alcohol, C₂H₅OH = 46 g/mol
molar mass of water = 18 g/mol
density of water = 1 g/mL
density of alcohol = 0.79 g/mL

<h3>Calculating moles of solute</h3>

85° proof vodka = 1/2 * 85% v/v

85° proof vodka = 42.5 % alcohol

In 100 mL vodka:

Volume of alcohol = 42.5 mL

volume of water = 57.5 mL

mass of alcohol, C₂H₅OH = density * volume

mass of alcohol, C₂H₅OH = 0.79 * 42.5

mass of alcohol, C₂H₅OH = 33.575 g

moles of alcohol = 33.575 g / 46 g/mol

moles of alcohol = 0.730 moles

<h3>Calculating mole fraction</h3>

mass of water = 57.5 ml * 1 g/mL

mass of water = 57.5 g

moles of water = 57.5 g/ 18 g/mL

moles of water = 3.194 moles

Total moles = 3.194 + 0.730

Total moles = 3.924 moles

Mole fraction of alcohol = 0.730/3.924

Mole fraction of alcohol = 0.186

<h3>Calculating molality of alcohol</h3>

mass of solvent = 57.5 = 0.0575 kg

Molality of alcohol = 0.730 / 0.0575

Molality of alcohol = 12.70 mol/kg

Therefore, the mole fraction and molality of alcohol, C₂H₅OH, in 85°proof vodka is 0.186 and 12.70 mol/kg respectively.

Learn more about mole fraction and molality at: brainly.com/question/10861444

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3 years ago

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