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Svetach [21]
3 years ago
5

How many hours are in 25 days??

Chemistry
1 answer:
borishaifa [10]3 years ago
8 0
There are 600 hours.

explanation

each day has 24 hours and we want to know how much hours is equivalent to 25 days so we multiply 24 times 25 which is 600.
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An ____,or an element located in group 7A, will form a salt when reacted with a metal atom.
stiv31 [10]

Answer:

B. Halogen

Explanation:

Halogens are the family of chemical elements found in the group VIIA of the periodic table which means they possess seven (7) outer electrons. Some examples of halogens are Fluorine (F), Iodine (I), Bromine (Br), and Chlorine (Cl).

A halogen, or an element located in group 7A, will form a salt when reacted with a metal atom.

For example, when Chlorine reacts with Sodium it would form a salt known as Sodium Chloride.

Na + Cl ----> NaCl

5 0
3 years ago
If a system requires 150 J of input work and produces 123 J of output work, what's its efficiency? A. 72% B. 122% C. 82% D. 92%
STALIN [3.7K]
The answer is C. 82......
4 0
3 years ago
Read 2 more answers
Bas +<br> PtF2 →<br> BaF2 +<br> Pts<br> Need to balance it
Basile [38]

it is already balanced

REACTANTS

Barium sulfide (BaS) + platinum (Ii) fluoride

PRODUCT

Barium fluoride (BaF2) + Cooperite (PtS)

Hope this answer helps you dear! take care

5 0
2 years ago
For a comparative or experimental investigation, scientists often make a testable ___ about a scientific question, and then they
Morgarella [4.7K]

Answer:

B. Hypothesis

Explanation: A hypothesis is a guess of what will or might happen before an experiment.

8 0
3 years ago
If a solution of hf (ka = 6.8 10-4) has a ph of 3.67, calculate the total concentration of hydrofluoric acid.
m_a_m_a [10]
When PH = ㏒(H^+)
[H+] = 10^-3.67
[H+] = 2.14x 10^-4

so according to the reaction equation:
                               HF               ↔        H^+          +          F^-
at equilibrium   X-(2.14x10^-4)           (2.14x10^-4)         (2.14x10^-4)

by substitution in Ka formula:
       Ka      = [H+][F]-/[HF]
6.8x10^-4 = (2.14x10^-4)*(2.14x10^-4) /(X-2.4x10^-4)
X-2.4x10^-4 = (4.58x10^-8)* (6.8x10^-4)
∴X = 2.4x10^-4
∴[HF] = X- (2.14x10^-4)= (2.4x10^-4)-(2.14x10^-4) = 2.6 X 10^-5

3 0
3 years ago
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